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andre [41]
2 years ago
8

How much heat energy is required to raise the temperature of 15g of silver from 25°C to 55°C, assuming the specific heat of silv

er
is 0. 24 J/gºC?

30

108

15 J

115 J
Chemistry
1 answer:
Alenkasestr [34]2 years ago
6 0

Answer:

108 j

Explanation:

.24 j/g-C  * 15 g * (55-25) =

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If a sample of oxygen occupies a volume of 85.0 L at a pressure of 67.4 kPa and a temperature of 245K , what volume would the ga
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Explanation:

Applying

P1= 67.4, V1= 85, T1= 245, P2= 179.6, V2= ?,. T2=273

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Substitute and simplify

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3 0
2 years ago
A 825 g iron block is heated to 352 degrees C and is placed in an insulated container (of negligible heat capacity) containing 4
Stella [2.4K]

Answer : The final equilibrium temperature of the water and iron is, 537.12 K

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of iron =  560 J/(kg.K)

c_1 = specific heat of water = 4186 J/(kg.K)

m_1 = mass of iron = 825 g

m_2 = mass of water = 40 g

T_f = final temperature of water and iron = ?

T_1 = initial temperature of iron = 352^oC=273+352=625K

T_2 = initial temperature of water = 20^oC=273+20=293K

Now put all the given values in the above formula, we get:

(825\times 10^{-3}kg)\times 560J/(kg.K)\times (T_f-625K)=-(40\times 10^{-3}kg)\times 4186J/(kg.K)\times (T_f-293K)

T_f=537.12K

Therefore, the final equilibrium temperature of the water and iron is, 537.12 K

8 0
2 years ago
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