Answer:
cu+2 ------ oxidation whereas Cu ------ reduction.
Explanation:
In the reaction, cu+2 is the place where oxidation occurs because this cupric ion losses electrons which causes +2 charge on it. we know that oxidation is the loss of electrons and reduction is the gaining of electrons so the Cu is the place or atom at which reduction occurs. Electrochemical cells have two electrodes, which is anode and the cathode. The anode is the electrode where oxidation occurs whereas the cathode is the electrode where reduction takes place.
Answer:
The answer is in the problem
Explanation:
As general rule of number of oxygen is -2:
O → -2
Alkali metals (Li, Na, K) are always +1
Na → +1
Alkali earth methals (Be, Mg, Ca...) are always +2
Ca → +2
The halogen group (F, Cl, Br...) is always -1
F → -1
The oxidation number of Si (+/- 4)
Aluminium is, usually +3
And to complete the octet rule in nitrogen, 3 electrons are required. That means:
N → -3
They all have the same number of electrons in their outer shell.
Partial pressure O2 = total pressure - vapour pressure H2O at 50 deg C
Vapour pressure H2O at 50 deg C = 12.332 kPa
= 96.00 kPa - 12.332 kPa = 83.67 kPa
