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shusha [124]
3 years ago
9

how many atoms of phosphorous are in 4.90 mol of copper(ii) phosphate? the formula for copper(ii) phosphate is Cu3(PO4)2.

Chemistry
1 answer:
Karolina [17]3 years ago
8 0

Answer:

\boxed{5.90 \times 10^{24}}

Explanation:

Step 1. Calculate the formula units of Cu₃(PO₄)₂  

\text{4.90 mol Cu$_{3}$(PO$_{4}$)$_{2}$} \times \dfrac{6.022 \times 10^{23} \text{ formula units}}{\text{1 mol Cu$_{3}$(PO$_{4}$)$_{2}$}}\\\\=\text{2.951 $\times$ 10$^{24}$ formula units Cu$_{3}$(PO$_{4}$)$_{2}$}

Step 2. Calculate the atoms of P

\text{Atoms of P}\\\\=\text{2.951 $\times$ 10$^{24}$ formula units Cu$_{3}$(PO$_{4}$)$_{2}$} \times \dfrac{ \text{2 atoms P}}{\text{1 formula unit Cu$_{3}$(PO$_{4}$)$_{2}$}}\\\\= \boxed{5.90 \times 10^{24} \text{ atoms P}}

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We know that the equation for density is:

D=\frac{m}{V}

where D is the density, m is the mass in grams, and V is the volume.

Given two of the variables, we can then solve for density:

D=\frac{0.196g}{100mL}= \frac{0.00196g}{mL}

So therefore, we now know that the density of carbon dioxide gas is 0.00196g/mL.

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3 years ago
Write a nuclear reaction for the neutron-induced fission of u−235 to form xe−144 and sr−90.
rusak2 [61]

Answer:

235/92U+10n→144/54Xe+90/38Sr+2/10n

Explanation:

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235/92U+10n→144/54Xe+90/38Sr+2/10n

  • In nuclear fission reactions a heavy nuclide is split into two light nuclides and is coupled by the release of energy.
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You have a solution of calcium chloride dissolved in water. You add some more solid to the solution and stir, and the solid diss
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Answer:

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A unit of heat energy that was formerly used frequently was the calorie. Look up the definition of the calorie in your textbook
dybincka [34]

Answer and Explanation:

Calorie is the unit of heat energy . There are 2 units with the same name 'calorie' which is widely used.

'The amount of heat energy required to increase the temperature of 1 gram of water by mass by 1^{\circ}C or 1 K is known as small calorie or gram calorie'.

Another one is large calorie which can be defined as :

'The amount of heat energy required to make arise in temperature of water 1 kg by mass by 1^{\circ}C or 1 K is known as large calorie or  kilcalorie and is represented as Cal or kcal'.

After the adoption of SI system, thee units of the metric system cal, C or kilocal are considered deprecated or obsolete with the SI unit for heat energy as 'joule or J'

1 cal = 4.184 J

1C or 1 kilocal = 4184 J

Calorimeter constant:

Calorimeter constant, represented as 'C_{cal}' is used to quantify the heat capacity or the amount of heat of a calorimeter.

It can be calculated by ther given formula:

{\displaystyle C_{cal}}={\frac {\Delta {H}}{\Delta {T}}}}}

where,

{\Delta {T}} = corresponding temperature change

{\Delta {H} = enthalpy change

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8 0
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