What is the mass, in grams, of 9.21×1024 molecules of methanol
1 answer:
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Answer :
(a) The moles of water produced are 145.35 moles.
(b) The mass of oxygen needed are 3080.8 grams.
<u>Solution for part (a) : Given,</u>
Moles of = 16.15 moles
First we have to calculate the moles of
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 2 moles of react to give 18 moles of
So, 16.15 moles of react to give
moles of
The moles of water produced are 145.35 moles.
<u>Solution for part (b) : Given,</u>
Mass of = 878 g
Molar mass of = 114 g/mole
Molar mass of = 32 g/mole
First we have to calculate the moles of .
Now we have to calculate the moles of
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 2 moles of react with 25 moles of
So, 7.702 moles of react with
moles of
Now we have to calculate the mass of .
The mass of oxygen needed are 3080.8 grams.