Question

What us the % composition of oxygen (O) in iron (III) hydroxide, Fe(OH) 3?

Answer 1

Answer:

44.91% of Oxygen in Iron (III) hydroxide

Explanation:

To solve this question we must find the molar mass of Fe(OH)3 and the molar mass of the oxygen in this molecule. Percent composition will be:

Molar mass Oxygen / molar mass Fe(OH)3 * 100

Molar mass Fe(OH)3 and oxygen:

1Fe = 55.845g/mol*1 = 55.845

3O = 16.00g/mol*3 = 48.00 - Molar mass of Oxygen

3H = 1.008g/mol*3 = 3.024

55.845 + 48.00 + 3.024 =

106.869g/mol is molar mass of Fe(OH)3

% Composition of oxygen is:

48.00g/mol / 106.869g/mol * 100 =

44.91% of Oxygen in Iron (III) hydroxide