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krek1111 [17]
3 years ago
14

Each point on the edge of a circle is equidistant from the center of the circle. The center of a circle is located at (6,3). Whi

ch point on the y-axis could be on the edge of the circle of the distance from the center of the circle to the edge is 10
Mathematics
2 answers:
denis-greek [22]3 years ago
6 0

Answer:

(0, –5)

Step-by-step explanation:

If you don't see this option there is another option, (0 , 11) is also correct

photoshop1234 [79]3 years ago
3 0

Good evening

Answer:

<h2>(0 , 5) and (0 , 11)</h2>

Step-by-step explanation:

Suppose M(x , y) is a point of the circle of center (6,3) and radius 10 and M is also a point of the y-axis then the coordonates of M should verify these two equations at the same time:

\left \{ {(x-6)^{2} +(y-3)^2=10^{2} } \atop {x=0}} \right.

Then

(0-6)² + (y-3)² = 100

then

36 + (y-3)² = 100

then

(y-3)² = 100 - 36

        = 64

then

|y-3| = 8

then

y - 3 = 8 or y - 3 = -8

then

y = 11   or  y = 5

then the only points that are on the edge of the circle and on y-axis are:

(0 , 5) and (0 , 11).

:)

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Which equation is equivalent to 2/3x-5/6=-5/12x+1/4
umka21 [38]

Answer:

x = 1

Step-by-step explanation:

\frac{2}{3} x -  \frac{5}{6}  =  -  \frac{5}{12} x +  \frac{1}{4}  \\  \frac{2}{3}x +  \frac{5}{12}  x =  \frac{1}{4}  +  \frac{5}{6}  \\  \frac{8}{12} x +  \frac{5}{12}x =  \frac{3}{12}  +  \frac{10}{12}  \\  \frac{13}{12} x =  \frac{13}{12}  \\ x = 1

6 0
3 years ago
Read 2 more answers
4.37) A set of data whose histogram is extremely skewed yields a mean and standard deviation of 70 and 12, respectively. What is
Brums [2.3K]

Answer:

75%

88.89%

Step-by-step explanation:

Given :

Mean = 70

Standard deviation = 12

Since the data is said to be extremely skewed, we apply Chebyshev's theorem rather than the empirical rule :

The minimum proportion of observation between 46 and 94

Chebyshev's theorem :

1 - 1 / k²

k = number of standard deviations from the mean

k = (94 - 70) / 12 = 24 / 12 = 2

Hence, we have ;

1 - 1/2²

1 - 1/4

1 - 0.25 = 0.75

Hence, The minimum proportion of observation between 46 and 94 is 75%

Between 36 and 106 :

k = (106 - 70) / 12 ;

k = 36/12 = 3

Hence,

1 - 1/3² = 1 - 1/9 = 8/9 = 0.8888 = 88.89%

The minimum proportion of observation between 34 and 106 is 88.89%

7 0
3 years ago
Can someone help me with number 5 please ???
Bumek [7]

Answer:


Step-by-step explanation:

el español es mi idiomad

3 0
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Maths, Spanish and English
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what do you need help for

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