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Reil [10]
3 years ago
15

To develop muscle tone, a woman lifts a 2.4 kg weight held in her hand. She uses her biceps muscle to flex the lower arm through

an angle of 21°. What is the instantaneous angular acceleration if she starts her workout with her arm vertical in the downwards direction? Assume the weight is 29 cm from the elbow joint, her forearm has a moment of inertia of 0.245 kg⋅m2, and the muscle force is 850 N at an effective perpendicular lever arm of 1.7 cm in rad/s2.
Physics
1 answer:
andrey2020 [161]3 years ago
6 0

Answer:

(a) a=41.1 rad/s^2

(b) W=15.7 J

Explanation:

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3 years ago
The knee extensors insert on the tibia at an angle of 30 degrees (from the longitudinal axis of the tibia), at a distance of 3 c
Reika [66]

Answer:

the knee extensors must exert 15.87 N

Explanation:

Given the data in the question;

mass m = 4.5 kg

radius of gyration k = 23 cm = 0.23 m

angle ∅ = 30°

∝ = 1 rad/s²

distance of 3 cm from the axis of rotation at the knee r = 3 cm = 0.03 m

using the expression;

ζ = I∝

ζ = mk²∝

we substitute

ζ = 4.5 × (0.23)² × 1

ζ  = 0.23805 N-m

so

from; ζ = rFsin∅

F = ζ / rsin∅

we substitute

F = 0.23805 / (0.03 × sin( 30 ° )

F = 0.23805 / (0.03 × 0.5)

F F = 0.23805 / 0.015

F = 15.87 N

Therefore, the knee extensors must exert 15.87 N

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2 years ago
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Answer:

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Explanation:

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