Three energy changes that result in movements accuring in your body as sit down reading book?
1 answer:
You might be interested in
Here is the full question:
The rotational inertia I of any given body of mass M about any given axis is equal to the rotational inertia of an equivalent hoop about that axis, if the hoop has the same mass M and a radius k given by:
The radius k of the equivalent hoop is called the radius of gyration of the given body. Using this formula, find the radius of gyration of (a) a cylinder of radius 1.20 m, (b) a thin spherical shell of radius 1.20 m, and (c) a solid sphere of radius 1.20 m, all rotating about their central axes.
Answer:
a) 0.85 m
b) 0.98 m
c) 0.76 m
Explanation:
Given that: the radius of gyration
So, moment of rotational inertia (I) of a cylinder about it axis =
k = 0.8455 m
k ≅ 0.85 m
For the spherical shell of radius
(I) =
k = 0.9797 m
k ≅ 0.98 m
For the solid sphere of radius
(I) =
k = 0.7560
k ≅ 0.76 m
(a) The period of the oscillation is 0.8 s.
(b) The frequency of the oscillation is 1.25 Hz.
(c) The angular frequency of the oscillation is 7.885 rad/s.
(d) The amplitude of the oscillation is 3 cm.
(e) The force constant of the spring is 148.1 N/m.
The given parameters:
- <em>Mass of the ball, m = 2.4 kg</em>
<em />
From the given graph, we can determine the missing parameters.
The amplitude of the wave is the maximum displacement, A = 3 cm
The period of the oscillation is the time taken to make one complete cycle.
T = 0.8 s
The frequency of the oscillation is calculated as follows;
The angular frequency of the oscillation is calculated as follows;
The force constant of the spring is calculated as follows;
Learn more about general wave equation here: brainly.com/question/25699025
