The answer would be erin out of all of them thank me later :)
in a one dimensional collision, a 4kg object with 5ms^1 and 6 kg object with 2ms^1 have initial velocity, the magnitude of impulse is 12 , 18
given,
mass 1 = 4kg
mass 2 = 6kg
velocity 1 = 5ms^1
velocity 2 = 2ms^1
impulse 1 = 4*(5-2)
= 12
Impulse 2 = 6*(5-2)
= 18
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Answer:
f = 1 m
Explanation:
The magnification of the lens is given by the formula:
![M = \frac{q}{p}](https://tex.z-dn.net/?f=M%20%3D%20%5Cfrac%7Bq%7D%7Bp%7D)
where,
M = Magnification = 4
q = image distance = 5 m
p = object distance = ?
Therefore,
![4 = \frac{5\ m}{p}\\\\p = \frac{5\ m}{4}\\\\p = 1.25\ m](https://tex.z-dn.net/?f=4%20%3D%20%5Cfrac%7B5%5C%20m%7D%7Bp%7D%5C%5C%5C%5Cp%20%3D%20%5Cfrac%7B5%5C%20m%7D%7B4%7D%5C%5C%5C%5Cp%20%3D%201.25%5C%20m)
Now using thin lens formula:
![\frac{1}{f}=\frac{1}{p}+\frac{1}{q}\\\\\frac{1}{f} = \frac{1}{1.25\ m}+\frac{1}{5\ m}\\\\\frac{1}{f} = 1\ m^{-1}\\\\](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bf%7D%3D%5Cfrac%7B1%7D%7Bp%7D%2B%5Cfrac%7B1%7D%7Bq%7D%5C%5C%5C%5C%5Cfrac%7B1%7D%7Bf%7D%20%3D%20%5Cfrac%7B1%7D%7B1.25%5C%20m%7D%2B%5Cfrac%7B1%7D%7B5%5C%20m%7D%5C%5C%5C%5C%5Cfrac%7B1%7D%7Bf%7D%20%3D%201%5C%20m%5E%7B-1%7D%5C%5C%5C%5C)
<u>f = 1 m</u>