Answer:
<h3>The power of headlight in series connection is 29.64 W</h3>
Explanation:
Given :
Power of headlight 
W
Power of starter 
W
Voltage of headlight and starter 
V
From equation of power,
For finding the resistance of headlight and starter,
⇒ For headlight,
Ω
⇒ For starter,
Ω
Since equivalent resistance,
Ω
So power in series is given by,
W
is this a true of false cuz if so this it true
By definition we have to:
LOG (k2 / k1)=(-Ea/R)*(1/T1-1/T2)
Where,
k1 = 0.0117 s-1
K2 = 0.689 s-1
T1 = 400.0 k
T2 = 450.0 k
R is the ideal gas constant
R = 8.314 KJ / (Kmol * K)
Substituting
ln (0.0117/0.689)=-Ea/(8.314)*((1/400)-(1/450))
Clearing Ea:
Ea = 122 kJ
answer
<span> the activation energy in kilojoules for this reaction is
</span> Ea = 122 kJ
<span>
</span>
Um this doesn't make since to me since you did not clearly state your awnser
