Answer:
independent=$50
dependent=$35X
Step-by-step explanation:
50 is the independent variable because it doesn't change.
35X is the dependent variable because it does change.
Hello!
Trapezoid ABCD is shown. A is at negative 5, 1. B is at negative 4, 3. C is at negative 2, 3. D is at negative 1, 1.
A) x-axis, y=x, y-axis, x-axis
b) x-axis, y-axis, x-axis
c) y=x, x-axis, x-axis
d) y-axis, x-axis, y-axis, x-axis
The best answer is C180 rotation wud take that point to 4th quadrant
reflection in x-axis takes that to 1st quadrant
<span>reflection in y-axis brings it back to 2nd quadrant again. So, the sequence of transformations will bring A back to where it started
</span>
Hope this Helps! :)
(x^2-3x+2)-1(3x^2-5x-1)=
x^2-3x+2-3x^2+5x+1=
x^2-3x^2-3x+5x+2+1=
-2x^2+2x+3
Answer:
Piper's claim is not correct.
Step-by-step explanation:
3(2(-3)+2) = 5(-3)+6
3(-6+2) = -15 + 16
-18 + 6 = 1
-12 = 1
The interval notation is 
Explanation:
The inequality is 
Let us complete the square, we get,
Simplifying, we have,
Adding both sides of the equation by 11, we get,
Since, we know that for 
, if n is even then ![-\sqrt[n]{a}](https://tex.z-dn.net/?f=-%5Csqrt%5Bn%5D%7Ba%7D%3Cu%3C%5Csqrt%5Bn%5D%7Ba%7D)
Thus, writing the above expression in this form, we get,
Also, if 
then 
and 
Then ,we have,
and 
Solving the inequalities, we get,
and 
Merging the intervals, we have,
Hence, writing the solution in interval notation, we have,
Therefore, the answer is
