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Nata [24]
3 years ago
9

Plz plz plz plz plz plzzzzzzz

Mathematics
2 answers:
Pepsi [2]3 years ago
5 0

Answer:

1 1/27

Step-by-step explanation:

1 1/6 + 2 1/8 = 1 1/27

laiz [17]3 years ago
4 0

Answer:

3 7/24

Step-by-step explanation

but is the last fraction 2 1/8?

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Hat is the interquartile range of the data represented by the box plot shown below?
marissa [1.9K]

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Where is the box plot?

Step-by-step explanation:

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4 years ago
Special Triangles
Ugo [173]

Answer:

see explanation

Step-by-step explanation:

Using the cosine and tangent trigonometric ratios and the exact values

cos30° = \frac{\sqrt{3} }{2} and tan30° = \frac{1}{\sqrt{3} } , then

cos30° = \frac{adjacent}{hypotenuse} = \frac{6}{m} = \frac{\sqrt{3} }{2} ( cross- multiply )

\sqrt{3} × m = 12 ( divide both sides by \sqrt{3} )

m = \frac{12}{\sqrt{3} } ← rationalise by multiplying numerator/ denominator by \sqrt{3} )

m = \frac{12}{\sqrt{3} } × \frac{\sqrt{3} }{\sqrt{3} } = \frac{12\sqrt{3} }{3} = 4\sqrt{3}

-------------------------------------------------------------------------------

tan30° = \frac{opposite}{adjacent} = \frac{n}{6} = \frac{1}{\sqrt{3} } ( cross- multiply )

\sqrt{3} × n = 6 ( divide both sides by \sqrt{3} )

n = \frac{6}{\sqrt{3} } ← rationalise the denominator

n = \frac{6}{\sqrt{3} } × \frac{\sqrt{3} }{\sqrt{3} } = \frac{6\sqrt{3} }{3} = 2\sqrt{3}

-----------------------------------------------------------------------------------

7 0
4 years ago
Need helppppppp asap thank youuuu!!
Lesechka [4]

Answer:

36, 57, 87

Step-by-step explanation:

8 0
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I need helppp on all of them is my homework and it’s due tmro helppp
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Answer:

Step-by-step explanation:

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My timetables and also my duzishin
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My timetables and also my duzishin are neat and tidy.

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