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a_sh-v [17]
3 years ago
15

What is the molar solubility of magnesium carbonate ( MgCO3 ) in water? The solubility-product constant for MgCO3 is 3.5 × 10-8

at 25°C.
Chemistry
2 answers:
DaniilM [7]3 years ago
8 0

Answer:

S MgCO3 = 1.8708 E-4 M at 25 °C

Explanation:

  • MgCO3 ↔ Mg2+  +  CO32-

           S                S             S

  • Ksp = 3.5 E-8

⇒ Ksp = 3.5 E-8 = [ Mg2+ ] * [ CO32- ] = S * S

⇒ Ksp = 3.5 E-8 = S²

⇒ S = √3.5 E-8

⇒ S = 1.8708 E-4 M

   

Umnica [9.8K]3 years ago
8 0

Answer:

1.75 ×10^-8 moldm-3

Explanation:

MgCO3(s) <----------> Mg^2+(aq) + CO3^2-(aq)

Ksp= 2x

x= Ksp/2

But Ksp= 3.5 × 10^-8 mol^2dm^-6

x= 3.5 × 10^-8/2

x= 1.75 ×10^-8 moldm-3

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Which of the following sets are isoelectronic (i.e., have the same number of electrons)? i. Br-, Kr, Sr2+ ii. C, N-, O2- iii. Mg
il63 [147K]

Answer:

ii. C,\ N^-,\ O^{2-}

Explanation:

Isoelectric species are the species which have same number of electrons.

From the given options:-

C,\ N^-,\ O^{2-} are the isoelectric species.

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8 0
3 years ago
How many moles of each reactant are needed to produce 3.60 x 10^2g ch3oh
zysi [14]
Methanol is prepared by reacting Carbon monoxide and Hydrogen gas,

                                   CO  +  2 H₂    →    CH₃OH

Calculating Moles of CO:
                                       According to equation,

             32 g (1 mole) of CH₃OH is produced by  =  1 Mole of CO
So,
             3.60 × 10² g of CH₃OH is produced by  =  X Moles of CO

Solving for X,
                       X  =  (3.60 × 10² g × 1 Mole) ÷ 32 g

                       X  =  11.25 Moles of CO

Calculating Moles of H₂:
                                       According to equation,

             32 g (1 mole) of CH₃OH is produced by  =  2 Mole of H₂
So,
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                       X  =  22.5 Moles of H₂

Result:
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is produced by reacting 11.25 Moles of CO and 22.5 Moles of H₂.
3 0
3 years ago
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Answer:

Explanation:

The cell reaction properly written is shown below:

              Cu|Cu²⁺_{aq} || Ag⁺_{aq} | Ag

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  Oxidation half:

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To derive the overall reaction, we must balance the atoms and charges:

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The net reaction equation:

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We then cancel out the electrons from both sides since they appear on both the reactant and product side:

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Answer:

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<em>hope it helps :)</em>

<em>please mark it the brainliest!</em>

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