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3 years ago

Find the gcf of the terms of the polynomial. 44x^5 16x^3

Mathematics

1 answer:

julia-pushkina [17]3 years ago

7 0

$44x^5=4x^3\cdot11x^2\\\\16x^3=4x^3\cdot4\\\\\boxed{GCF(44x^5;\ 16x^3)=4x^3}\to\fbox{c.}$

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GREYUIT [131]

Sixty-eight square units

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3 years ago

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Lena [83]

Answer:

$\bold{\frac{3}{16} }$

Explanation:

1 / 16 (3)

= (1 / 16) (3 / 1)

= (1)(3) / (16)(1)

= 3 / 16

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3 years ago

Solve: 8+ x/2= 1/4 (x-4)-1

alexandr402 [8]

|3x+1|=4 : x=−
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Pasos
|3x+1|=4
Aplicar las propiedades de los valores absolutos: Pi |u| = a, a>0 entonces u = a or u = −a
3x+1=−4 or 3x+1=4
Mostrar pasos
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2 years ago

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3 years ago

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You are planning a survey of starting salaries for recent computer science majors. In a recent survey by the National Associatio

nydimaria [60]

Answer:

A sample size of 554 is needed.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.025 = 0.975$ , so Z = 1.96.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Standard deviation is known to be $12,000

This means that $\sigma = 12000$

What sample size do you need to have a margin of error equal to $1000, with 95% confidence?

This is n for which M = 1000. So

$M = z\frac{\sigma}{\sqrt{n}}$

$1000 = 1.96\frac{12000}{\sqrt{n}}$

$1000\sqrt{n} = 1.96*12$

Dividing both sides by 1000:

$\sqrt{n} = 1.96*12$

$(\sqrt{n})^2 = (1.96*12)^2$

$n = 553.2$

Rounding up:

A sample size of 554 is needed.

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2 years ago