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Svet_ta [14]
3 years ago
6

How much stronger is methane than carbon dioxide as a greenhouse gas?

Chemistry
1 answer:
Vaselesa [24]3 years ago
8 0

Answer:

the answer is d. but try 20

Explanation:

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At 570. mm Hg and 25°C, a gas sample ne (in mm Hg) at a volume of 1250 mL and a temperature of 175°C and 25°C, a gas sample has
maw [93]

Answer:

final pressure ( P2) = 467.37 mm Hg

Explanation:

ideal gas:

  • PV = nRT

∴ P1 = 570 mm Hg * ( atm / 760 mm Hg ) = 0.75 atm

∴ T1 = 25 ° C = 298 K

∴ V1 = 1.250 L

∴ R = 0.082 atm L / K mol

⇒ n = P1*V1 / R*T1

⇒ n = (( 0.75 ) * ( 1.25 )) / (( 0.082 ) * ( 298 ))

⇒ n = 0.038 mol gas

∴ T2 = 175 °C ( 448 K )

∴ V2 = 2.270 L

⇒ P2 = nRT2 / V2

⇒ P2 = (( 0.038 ) * ( 0.082 ) * ( 448 )) / 2.270

⇒ P2 = 0.615 atm * ( 760 mm Hg / atm ) = 467.37 mm Hg

5 0
3 years ago
Which statement about subatomic particles is true?
Lera25 [3.4K]

Answer:

C

Explanation:

6 0
2 years ago
5. A sample of gas occupies 1.55 L at 27 degrees Celsius and 1.00 atm pressure. What will the volume be if the pressure is incre
Sergio039 [100]

Answer:

The volume will be 0.031 L

Explanation:

Since temperature is constant, Boyle's law is applied in this case.

Boyle's law States that at constant temperature, the volume of a given mass of a gas is inversely proportional to it's pressure.

From this statement it was deduced that P1V1 = P2V2

From the question, P1 = 1atm, V1 = 1.55L, P2 = 50 atm and V2 is to be calculated.

V2 = P1V1/P2

= 1×1.55÷50

=0.031 L

5 0
3 years ago
A 0.8115 g sample of HCl was placed into a 50 mL volumetric flask and the sample was thoroughly dissolved in water to make 50 mL
inysia [295]

Answer:

Molarity of NaOH solution is 1.009 M

Explanation:

Molar mass of HCl is 36.46 g/mol

Number moles = (mass)/(molar mass)

So, 0.8115 g of HCl = \frac{0.8115}{36.46}moles HCl = 0.02226 moles HCl

1 mol of NaOH neutralizes 1 mol of HCl.

So, if molarity of NaOH solution is S(M) then moles of NaOH required to reach endpoint is \frac{S\times 22.07}{1000}moles

So, \frac{S\times 22.07}{1000}=0.02226

or, S = 1.009

So, molarity of NaOH solution is 1.009 M

5 0
3 years ago
write the steps you would use for making tea.use the words solution,solvent,solute,dissolve,soluble,insoluble,filtrate and resid
poizon [28]
1. Take 100ml of water as solvent and boil it few minutes.
2. Now add one tea spoon sugar, one tea spoon tea leaves and 50ml of milk. Here sugar, tea leaves and milk are solute.
3. Now boil it again for few minutes so that sugar will dissolves in solution as sugar is soluble in water
4. Now filter the solution. Collect the filtrate in cup. The insoluble tea leaves will be left behind as residue.
4 0
3 years ago
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