Answer:
The molar mass in g/mol is 121.4 g/m
Explanation:
Let's apply the Ideal Gases Law to solve this:
P . V = n . R. T
V = 125 mL → 0.125L
P = 754 Torr
760 Torr ___ 1 atm
754 Torr ____ (754 / 760) = 0.992 atm
Moles = Mass / Molar mass
0.992 atm . 0.125L = (0.495 g / MM) . 0.082 . 371K
(0.992 atm . 0.125L) / (0.082 . 371K) = (0.495 g / MM)
4.07x10⁻³ mol = 0.495 g / MM
MM = 0.495 g / 4.07x10⁻³ mol → 121.4 g/m
Hey there!
3d band can hold as many as 10 electrons, while 4s can bear as many as two electrons.
The maximum number of electrons for this composite band should be 12 electrons.
Hope that helps!
Answer:
1s2 2s2 2p6 3s2 3p6 4s2 3d5
Explanation:
According to the Aufbau principle, electrons are filled in orbitals in order of increasing energy. The energy of orbitals in the electronic configuration of manganese increases from left to right, hence 3d orbital is much greater in energy than a 3p orbital.
The arrangement of orbitals in order of increasing energy is shown in the answer above.
According to the law of conservation of mass, the amount of BARIUM present of the reactants is the same as the amount present in the products (the precipitate).
(11.21 g BaSO4) / (233.4 g/mol BaSO4) = 0.0480 mol BaSO4 and original barium salt
(10.0 g) / (0.0480 mol) = 208.3 g/mol
So it must have been BaCl2, because the molar mass of Barium is 137 which leave 71 grams left. Since Barium is a +2 charge, it means the atom next to it must be twice. Chlorine mass is 35, which twice is 71