Answer:
25% gold.
Explanation:
6 is 25 percent of 24, so 6 karat gold would be 25% gold.
Answer:
4KO₂ + 2CO₂ -> 2K₂CO₃ + 3O₂
<u> Step 1: Find the moles of O₂.</u>
n(O₂) = mass/ Mr.
n(O₂) = 100 / 32 = 3.125 mol
<u>Step 2: Find the ratio between KO₂ and O₂.</u>
<u>KO₂ </u> : <u> O₂</u>
4 : 3
4/3 : 1
(4*3125)/3 : 3.125
=4.167 mol of KO₂
Thus now we know, to produce 100 g of O₂, we need 4.167mol of KO₂
<u>Step 3: Find the mass of KO₂:</u>
<u />
mass = mol * Mr. (KO₂)
Mass = 4.167* 71.1
Mass = 296.25 g
Iron Fluoride
A chemical compound is a substance composed of atoms from two or more (different) elements. These compounds are formed by the creation of chemical bonds between the atoms of the different elements.
Helium and Neon are both elements, and in particular, they belong to a group of chemical elements called noble gases. Being noble gases, they are very stable and do not react easily.
Iron fluoride is a chemical compound consisting of the metal, iron, and the nonmetal, fluorine. When a metal and a nonmetal react to form a compound, they form ionic bonds to hold together the atoms of the different elements comprising the compound.
This problem can be solved by using ideal gas equation PV=nRT. The unit used in the numbers is already matched so you don't need to convert any of them. The calculation would be:
PV= nRT
102.3 kPa * V = 0.00831 mol *298.15 K* (8.314 L*kPa/mol*K) V= 20.60 L-kPa / 102.3 kPa V= 0.201358 L