Answer:
7.22 feet long
Explanation:
1 meter = 3.28084 feet
2.2 × 3.28084 = 7.2<u>1</u>785
= 7.22
I hope this is helpful :)
The semifluid or hot fluid substance within or below the crust of the Earth from which lava and other igneous rock are produced by cooling is known as magma.
The temperature and pressure elevate with depth, finally reaching to a level wherein the strongest rock is melted, transforming into magma. When the magma comes into contact with water, it instantly gets transformed into a rock, that is, the outside solidifies briskly, and the inside of it gets cold.
Answer:
1.08 MW
Explanation:
Given that:
Heat supplied to heat engine
= 5 MW
Temperature of the hot source of engine
= 323 K
Temperature of the cold source of engine
= 303 K
the temperature and heat relation for a reversible heat engine can be presented as follows:
![\frac{T_L}{T_{WS}} =\frac{Q_L}{Q_{WS}}](https://tex.z-dn.net/?f=%5Cfrac%7BT_L%7D%7BT_%7BWS%7D%7D%20%3D%5Cfrac%7BQ_L%7D%7BQ_%7BWS%7D%7D)
![\frac{303}{323} =\frac{Q_L}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B303%7D%7B323%7D%20%3D%5Cfrac%7BQ_L%7D%7B5%7D)
= 4.69 MW
TO determine the work done by the heat engine ; we have:
![W_{engine}=Q_{WS}-Q_{L}](https://tex.z-dn.net/?f=W_%7Bengine%7D%3DQ_%7BWS%7D-Q_%7BL%7D)
![W_{engine}=5 -4.69](https://tex.z-dn.net/?f=W_%7Bengine%7D%3D5%20-4.69)
![W_{engine}=0.309MW](https://tex.z-dn.net/?f=W_%7Bengine%7D%3D0.309MW)
The temperature and heat relation for the reversible heat pump can be written as:
![\frac{T_H}{T_L}=\frac{Q_H}{Q_L}](https://tex.z-dn.net/?f=%5Cfrac%7BT_H%7D%7BT_L%7D%3D%5Cfrac%7BQ_H%7D%7BQ_L%7D)
![\frac{T_H}{T_L}=\frac{Q_H}{Q_H-W}](https://tex.z-dn.net/?f=%5Cfrac%7BT_H%7D%7BT_L%7D%3D%5Cfrac%7BQ_H%7D%7BQ_H-W%7D)
![\frac{423}{303} =\frac{Q_H}{Q_H-W}](https://tex.z-dn.net/?f=%5Cfrac%7B423%7D%7B303%7D%20%3D%5Cfrac%7BQ_H%7D%7BQ_H-W%7D)
![Q_H=1.396-0.309\\Q_H=1.08MW](https://tex.z-dn.net/?f=Q_H%3D1.396-0.309%5C%5CQ_H%3D1.08MW)
Following the composition by mass, the molecular formula of monosodium glutamate would be ![C_7H_8O_4NNa](https://tex.z-dn.net/?f=C_7H_8O_4NNa)
The empirical formula can first be derived such that:
C = 51/12 = 4.25
H = 4.778/1 = 4.77
O = 37.8/16 = 2.36
N = 8.29/14 = 0.59
Na = 13.60/23 = 0.59
Dividing by the smallest (0.59):
C = 7
H = 8
O = 4
N = 1
Na = 1
Hence, the empirical formula would be ![C_7H_8O_4NNa](https://tex.z-dn.net/?f=C_7H_8O_4NNa)
Molar mass of empirical formula = 12x7 + 8x1 + 16x4 + 14 + 23
= 195
Recall that: , (
)n = molecular formula
Where n = molar mass/empirical formular mass
Molar mass/empirical formular mass = 169/195
= 0.87
≈ 1
Thus, (
) x 1 = ![C_7H_8O_4NNa](https://tex.z-dn.net/?f=C_7H_8O_4NNa)
More on molecular formula calculation can be found here: brainly.com/question/21629131