Question

Find the sum: (4x3−3x+2x3)+(2x−2x2+6x)

Answer 1

9x+5

Step-by-step explanation:

Answer 2

Answer:

The Sum of the  Expression  $(4x^3-3x+2x^3)+(2-2x^2+6x)$ is $(6x^3+2x^2+5x)$

Explanation:

Given :

$(4x^3-3x+2x^3)+(2x-2x^2+6x)$

Now we will use the BODMAS method Which has a rule to use it and this rule states that if any equation has bracket, off, Divide ,Multiply , addition and subtraction signs then we will solve first Bracket  then Off then Division then Multiplication then Addition and at last subtraction.  

So,  

Sum=$(4x^3-3x+2x^3)+(2x-2x^2+6x)$

Sum=$(6x^3-3x)+(-2x^2+8x)$

Sum=$(6x^3-3x-2x^2+8x)$

Sum=$(6x^3-2x^2+5x)$

Hence the Sum of the above Expression is $(6x^3-2x^2+5x)$