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Anuta_ua [19.1K]
3 years ago
14

Find the sum: (4x3−3x+2x3)+(2x−2x2+6x)

Mathematics
2 answers:
shepuryov [24]3 years ago
6 0

9x+5

Step-by-step explanation:

kodGreya [7K]3 years ago
3 0

Answer:

The Sum of the  Expression  (4x^3-3x+2x^3)+(2-2x^2+6x) is (6x^3+2x^2+5x)

<u>Explanation</u>:

Given :

(4x^3-3x+2x^3)+(2x-2x^2+6x)

Now we will use the BODMAS method Which has a rule to use it and this rule states that if any equation has bracket, off, Divide ,Multiply , addition and subtraction signs then we will solve first Bracket  then Off then Division then Multiplication then Addition and at last subtraction.  

So,  

Sum=(4x^3-3x+2x^3)+(2x-2x^2+6x)

Sum=(6x^3-3x)+(-2x^2+8x)

Sum=(6x^3-3x-2x^2+8x)

Sum=(6x^3-2x^2+5x)

Hence the Sum of the above Expression is (6x^3-2x^2+5x)

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A man is trying to calculate the shadow of a 24 flag pole. He uses similar triangles by comparing his own height 5 ft to the len
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Answer:

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