3 years ago

Diagram showing forces acting on a coasting bike traveling 25 km/h on a flatter surface

1 answer:

7 0

I included air resistance because the bike is moving kinda fast so it probably matters for your problem

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VARVARA [1.3K]

Answer:

Explanation:

just trying to follow basic grammar.

5 0

3 years ago

Nikitich [7]

Answer:

$x=\frac {kd^{2}}{2(mgsin\theta +\mu_{k}mgcos\theta)}$

Explanation:

From the law of conservation of energy

Energy lost by the spring, W=Kinetic energy gained, KE+Potential energy gained, PE+Work done by friction, Fr

$0.5kd^{2}=0.5mv^{2}+mgLsin\theta+\mu_{k}mgcos\theta x$

$x(mgsin\theta+\mu_{k}mgcos\theta)=0.5kd^{2}$

$x=\frac {kd^{2}}{2(mgsin\theta +\mu_{k}mgcos\theta)}$

The required distance from A to B is $x=\frac {kd^{2}}{2(mgsin\theta +\mu_{k}mgcos\theta)}$

5 0

3 years ago

tangare [24]

No, one more group must get the same result as the other group. This will make it more reliable and reproducible.

4 0

3 years ago

viktelen [127]

It would take roughly 3 seconds.

4 0

3 years ago

masha68 [24]

15 km 30 divided by 4 is 7.5 km in 30 min times that by 2 the answer is 15

6 0

4 years ago