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e-lub [12.9K]
3 years ago
6

Earth's lower atmosphere contains negative and positive ions that are produced by radioactive elements in the soil and cosmic ra

ys from space. In a certain region, the atmospheric electric field strength is 118 V/m and the field is directed vertically down. This field causes singly charged positive ions, at a density of 503 cm-3, to drift downward and singly charged negative ions, at a density of 628 cm-3, to drift upward (see the figure). The measured conductivity of the air in that region is 2.69 × 10-14 (Ω-m)-1. Calculate (a) the magnitude of the current density and (b) the ion drift speed, assumed to be the same for positive and negative ions.
Physics
1 answer:
Morgarella [4.7K]3 years ago
5 0

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An air bubble at the bottom of a lake 36.0 m deep has a volume of 1.22 cm^3. If the temperature at the bottom is 5.9°C and at th
AlexFokin [52]

Answer:

volume of the bubble just before it reaches the surface is 5.71 cm³

Explanation:

given data

depth h = 36 m

volume v2 = 1.22 cm³ = 1.22 × 10^{-6} m³

temperature bottom t2 = 5.9°C = 278.9 K

temperature top  t1 = 16.0°C = 289 K

to find out

what is the volume of the bubble just before it reaches the surface

solution

we know at top atmospheric pressure is about P1 = 10^{5} Pa

so pressure at bottom P2 = pressure at top + ρ×g×h

here ρ is density and h is height and g is 9.8 m/s²

so

pressure at bottom P2 = 10^{5} + 1000 × 9.8 ×36

pressure at bottom P2 =4.52 × 10^{5}  Pa

so from gas law

\frac{P1*V1}{t1} = \frac{P2*V2}{t2}

here p is pressure and v is volume and t is temperature

so put here value and find v1

\frac{10^{5}*V1}{289} = \frac{4.52*10^{5}*1.22}{278.9}

V1 = 5.71 cm³

volume of the bubble just before it reaches the surface is 5.71 cm³

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3 years ago
Find the magnitude of the side and the angle. Please help!
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Answer:

Explanation:

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Klio2033 [76]

Answer:

Explanation:

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b. Wavelength is measured from the highest point of one wave to the highest point of the next wave (or from the lowest point of one wave to the lowest point of the next wave, since they are the same). The wavelength of this wave then is 20.0 cm. or \lambda=20.0cm

c. The period, or T, of a wave is found in the equation

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50.0=\frac{1}{T} so

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d. The speed of the wave is found in the equation

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And there you go!

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3 years ago
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