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e-lub [12.9K]
4 years ago
6

Earth's lower atmosphere contains negative and positive ions that are produced by radioactive elements in the soil and cosmic ra

ys from space. In a certain region, the atmospheric electric field strength is 118 V/m and the field is directed vertically down. This field causes singly charged positive ions, at a density of 503 cm-3, to drift downward and singly charged negative ions, at a density of 628 cm-3, to drift upward (see the figure). The measured conductivity of the air in that region is 2.69 × 10-14 (Ω-m)-1. Calculate (a) the magnitude of the current density and (b) the ion drift speed, assumed to be the same for positive and negative ions.
Physics
1 answer:
Morgarella [4.7K]4 years ago
5 0

Nnajsjxjxkxosoosndjxuxixjsnususbshsuauzjzjjzz

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Answer:D. λfilm/4

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The film thickness will need to be increased by λfilm/4 for it to be able to give a destructive interference.

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3 years ago
16x^2y^2-25a^2b^2<br>factorize the expression​
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(4xy+5ab)(4xy-5ab)

Explanation:

16x^{2}y^{2}-25a^{2}b^{2}

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So, this factorized is:

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8 0
3 years ago
how much gravitational potential energy do you give a 70 kg person when you lift him up 3 m in the air?
SCORPION-xisa [38]

Given gravitational potential energy when he's lifted is 2058 J.

Kinetic energy is transferred to the person.

Amount of kinetic energy the person has is -2058 J

velocity of person = 7.67 m/s².

<h3>Explanation:</h3>

Given:

Weight of person = 70 kg

Lifted height = 3 m

1. Gravitational potential energy of a lifted person is equal to the work done.

PE_g=W=m\times g\times h\\Acceleration due to gravity = g = 9.8 \ m/s^2 \\PE_g= m = m\times g\times h= 70\times 9.8 \times 3 = 2058\ kg.m/s^2 = 2058\ J

Gravitational potential energy is equal to 2058 Joules.

2. The Gravitational potential energy is converted into kinetic energy. Kinetic energy is being transferred to the person.

3. Kinetic energy gained = Potential energy lost = -PE_g = -2058\ kg.m/s^2

Kinetic energy gained by the person = (-2058 kg.m/s²)

4. Velocity = ?

Kinetic energy magnitude= \frac{1}{2} m\times v^2 = m\times g \times h

Solving for v, we get

v=\sqrt{2gh} =\sqrt{2\times 9.8 \times 3} = \sqrt{58.8} = 7.67 m/s^2

The person will be going at a speed of 7.67 m/s².

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As the elephant falls from 10 m does it lose or gain KE? Explain.
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He loss KE hope this helps

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