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ollegr [7]
3 years ago
6

Miki has a dozen oranges of the same size and a dozen pears of the same size. Miki uses her juicer to extract 8 ounces of pear j

uice from 3 pears and 8 ounces of orange juice from 2 oranges. She makes a pear-orange juice blend from an equal number of pears and oranges. What percent of the blend is pear juice? (A) 30 (B) 40 (C) 50 (D) 60 (E) 70
Mathematics
1 answer:
vagabundo [1.1K]3 years ago
8 0

Answer:

Step-by-step explanation:

A pear gives $8/3$ ounces of juice per pear. An orange gives $8/2=4$ ounces of juice per orange. If the pear-orange juice blend used one pear and one orange each, the percentage of pear juice would be

{8/3}/{8/3+4} X 100 = {8}/{8+12} X 100  = 40%

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The area of the trapezoid
ELEN [110]

Answer:

<h2>A = 82.5 in²</h2>

Step-by-step explanation:

The formula of an area of a trapezoid:

A=\dfrac{b_1+b_2}{2}\cdot h

b₁, b₂ - bases

h - height

We have b₁ = 10in, b₂ = 5in and h = 11in. Substitute:

A=\dfrac{10+5}{2}\cdot11=\dfrac{15}{2}\cdot11=7.5\cdot11=82.5\ in^2

7 0
4 years ago
Read 2 more answers
What is one composite number that’s odd?
ELEN [110]
15 is a composite number
5 0
4 years ago
What is equivalent to -1/4y -2 1/4y + 1/2 (4-2y) a) -3y + 2 b) -3 1/2y + 2 c) -4y + 4
Amanda [17]

Answer:

B. -3 1/2y + 2

Step-by-step explanation:

Our expression is: \frac{-1}{4} y-2\frac{1}{4} y+\frac{1}{2} (4-2y).

Let's first distribute out that parentheses. Remember that distribution is simply taking the sum of the product of the outside term with each of the inside terms. Here, the outside term is 1/2 and the inside terms are 4 and -2y:

\frac{1}{2} (4-2y)=\frac{1}{2} *4+\frac{1}{2} *(-2y)=2-y

Now, we have:

\frac{-1}{4} y-2\frac{1}{4} y+2-y

We want to combine like terms, which means combining all the terms with y in them:

\frac{-1}{4} y-2\frac{1}{4} y-y+2=\frac{-1}{4} y-\frac{9}{4} y-\frac{4}{4} y+2=\frac{-1-9-4}{4} y+2=\frac{-14}{4} y+2=\frac{-7}{2} y+2

Remember that -7/2 can be written as the mixed number -3 1/2, so our final answer is:

-3 1/2y + 2

The answer is thus B.

<em>~ an aesthetics lover</em>

7 0
3 years ago
What are the factors of x2 – 100?
Komok [63]

Answer:

(x+10)(x-10)

Step-by-step explanation:

Given : x^{2} -100

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Solution:

x^{2} -100

Since 100 =10^{2}

x^{2} -10^{2}

using property : a^{2} -b^{2} =(a+b)(a-b)

(x+10)(x-10)

Thus  the factors of x^{2} -100 are (x+10) and (x-10)


6 0
3 years ago
Read 2 more answers
Please help
lys-0071 [83]
Part 1
1) The positive integers          ----------->  <span>D.) The natural numbers
</span>2.) An ordering of quantities  -----------> <span>B.) A sequence
</span>3.) 2, 4, 8, 16, . . ., 256            ----------->  <span>A.) An example of a finite sequence
</span>4.) 1, 3, 5, 7, . . .                        ----------->  <span>E.) An example of an infinite sequence
</span>5.) No first term is available   ----------->  C.) The reason the numbers . . . -4, -2, 0, 2, 4, . . . are not a sequence
Part 2
a_n=n^2+2\\ a_1=1+2=3\\ a_2=4+2=6\\ a_3=9+2=11\\ a_4=16+2=18\\ a_5=25+2=27
The answers is A.
Part 3
a_n=-1(\frac{1}{3})^{n-1} \\ a_1=-1(\frac{1}{3})^{1-1}=-1\\ a_2=-1(\frac{1}{3})^{2-1}=-\frac{1}{3}\\ a_3=-1(\frac{1}{3})^{3-1}=--\frac{1}{9}\\ a_4=-1(\frac{1}{3})^{4-1}=--\frac{1}{27}\\ a_5=-1(\frac{1}{3})^{5-1}=--\frac{1}{81}\\
The answers is B.
Part 4
The pattern in this sequence is:
a_n=2a^nb^{n-1}
Let's list first six terms:
a_n=2a^nb^{n-1}\\&#10;a_1=2a^1b^0=2a\\&#10;a_2=2a^2b^1=2a^2b\\&#10;a_3=2a^3b^2\\&#10;a_4=2a^4b^3\\&#10;a_5=2a^5b^4\\&#10;a_6=2a^6b^5\\
This is a infinite sequence. The patern is obvious and we could find any term within the sequence.


5 0
3 years ago
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