Answer:
λ = 3 10⁻⁷ m, UV laser
Explanation:
The diffraction phenomenon is described by the expression
a sin θ = m λ
let's use trigonometry
tan θ = y / L
as in this phenomenon the angles are small
tan θ =
= sin θ
sin θ = y / L
we substitute
a y / L = m λ
let's apply this equation to the initial data
a 0.04 / L = 1 600 10⁻⁹
a / L = 1.5 10⁻⁵
now they tell us that we change the laser and we have y = 0.04 m for m = 2
a 0.04 / L = 2 λ
a / L = 50 λ
we solve the two expression is
1.5 10⁻⁵ = 50 λ
λ = 1.5 10⁻⁵ / 50
λ = 3 10⁻⁷ m
UV laser
Answer:
(1) 0.333 Hz
(2) 4 sec
(3) 2 sec, 0.5 Hz
Explanation:
(1) We have given time period of pendulum is 3 sec
So T = 3 sec
Frequency will be equal to 
(2) Frequency of the pendulum is given f = 0.25 Hz
Time period is equal to 
(3) It is given that a pendulum makes 10 back and forth swings in 20 seconds
So time taken to complete 1 back and forth swings = 
So time period T = 2 sec
Frequency will be equal to 
Answer:
1) El diámetro es de aproximadamente 913,987 cm.
2) La fuerza del cilindro es 5576850 kgf
Explanation:
1) Los parámetros dados son;
El volumen del aire = 13,122 litros = 13122000 cm³
La presión de trabajo = 8.5 kgf / cm²
La longitud del cilindro = 20 cm.
Por lo tanto, tenemos;
El área de la base del cilindro = π · r² = 13122000 cm³ / (20 cm) = 656100 cm²
r = √ (656100 / π) ≈ 456,994 cm
El diámetro = 2 × r ≈ 2 × 456.994 ≈ 913.987 cm
El diámetro ≈ 913,987 cm
2) La fuerza del cilindro = El área de la base del cilindro × La presión de trabajo
∴ La fuerza del cilindro = 656100 cm² × 8.5 kgf / cm² = 5576850 kgf
La fuerza del cilindro = 5576850 kgf
Answer:
<em>The second option has a lower power output. P=30 W</em>
Explanation:
<u>Mechanical Power
</u>
It is a physical magnitude that measures the rate a work W is done over time t.

Since W=F.d

The first option means the worker will lift the box by a distance of 1.2 meters in 3 seconds by applying 250 N of force. That produces a power of

The second option requires the worker applies 75 N of force and travel a distance of 4 meters for 10 seconds, thus the power is

The second option has a lower power output