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Thepotemich [5.8K]
3 years ago
8

An airplane is accelerating forward due to a force of 3320 newtons acting

Physics
1 answer:
Darya [45]3 years ago
5 0

Two opposite forces generate a force whose magnitude is the difference of the two magnitudes, and whose direction is the same of the strongest one.

We have 3320 newtons forward, and 550 backwards.

So, the net force is forward, and has magnitude 3320-550=2770

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Which best describes a chain reaction associated with a nuclear reaction?
mojhsa [17]
I think fission chain reaction is the correct answer.
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3 years ago
Which can be observed both on Earth and in an accelerating ship in space that is free from the effect of any gravitational field
Reil [10]

Answer:

  • apples falling from trees
  • people's feet touching the ground
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Explanation:

When a space ship is accelerating in space, there is a force known as Inertia that kicks in. Inertia will mirror the effects of gravity on the ship even if there is no gravitational field effect such that anything that would happen where there is gravity, would continue to happen.

This means that apples will fall from trees, people's feet will touch the ground, sky divers will be pulled downwards and balls will bend downwards when thrown as well. These are the same effects expected on earth where gravity pulls things towards the earth's core.

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2 years ago
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Why does the density of a substance remain the same for different amount of the substance
tresset_1 [31]

Think of it this way: 
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you buy, the whole bagful is still $1 PER POUND.

-- If a certain salad dressing has 40 calories PER Tablespoon, it doesn't
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-- Density means '(mass) PER unit of volume'.  Whether you have a tiny
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6 0
3 years ago
during the course of songraphic exam, you notice lateral splaying of echoes in the far field. what can you do to improve the ima
horrorfan [7]

Answer:

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8 0
3 years ago
Calculate the magnitude of the acceleration due to gravity on the surface of Earth due to the Moon.
Fudgin [204]

Answer:

g'_h=1.096\times 10^{-5}\ m.s^{-2}

Explanation:

We know that the gravity on the surface of the moon is,

  • g'=\frac{g}{6}
  • g'=1.63\ m.s^{-2}

<u>Gravity at a height h above the surface of the moon will be given as:</u>

g'_h=\frac{G.m}{(r+h)^2} ..........................(1)

where:

G = universal gravitational constant

m = mass of the moon

r = radius of moon

We have:

  • G=6.67\times 10^{-11}\ m^3.s^{-2}.kg^{-1}
  • m=7.35\times 10^{22}\ kg
  • r=1.74\times 10^6\ m
  • h=384.4\times 10^6\ m is the distance between the surface of the earth and the moon.

Now put the respective values in eq. (1)

g'_h=\frac{6.67\times 10^{-11}\times 7.35\times 10^{22}}{(1.74\times 10^6+384.4\times 10^6)^2}

g'_h=1.096\times 10^{-5}\ m.s^{-2} is the gravity on the moon the earth-surface.

4 0
3 years ago
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