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salantis [7]
3 years ago
8

Find the minimum acceleration attained on the interval 0<=t<=4 by the particale whos velocity is given by v(t)=t^2-4t^2-3t

+3
Physics
1 answer:
anyanavicka [17]3 years ago
8 0
We  know that vt = t^2 - 4t^2 - 3t + 3

a = v' = 3t^2 - 8t - 3

a'=  6t - 8 = 0

6t = 8

t = 8/6

hope this helps

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