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tino4ka555 [31]
3 years ago
8

A piston motion moves a 25-kg hammerhead vertically down 1 m from rest to a velocity of 50 m/s in a stamping machine. What is th

e change in total energy of the hammerhead?
Physics
1 answer:
Alja [10]3 years ago
3 0

Answer:

31.005 KJ

Explanation:

We are given that

Mass of hammerhead=25 kg

Initial velocity,u=0

Final velocity,v=50 m/s

h=-1 m

h'=0

We have to find the change in total energy of the hammerhead.

Change in total energy=E_2-E_1=m(u_2-u_1)+\frac{1}{2}m(v^2-u^2)+mg(h-h')

Using the formula

Change in internal energy of hammerhead=m(u_2-u_1)=0

Change in total energy=\frac{1}{2}(25)(50)^2+25\times 9.8(-1)

Where g=9.8m/s^2

Change in total energy=31005 J=\frac{31005}{1000}=31.005 KJ

1 KJ=1000 J

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Speed is an important component of which of the following sports? A. tennis B. soccer C. swimming D. all of the above Please sel
sladkih [1.3K]

D. all of the above

Explanation:

The best answer from the choices is option D all of the above.

Speed is a key component aspect of almost all sport.

What is speed:

Speed is the rate of change of distance with time;

 Speed = \frac{distance}{time}

distance is the path taken by a body

time is the duration of interval

In tennis, speed is very essential and critical same as soccer and swimming. In fact, sports with more speed have very good advantage at excelling.

learn more:

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7 0
4 years ago
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A body is moving along a circular path with variable speed, it has both radial and tangential acceleration.
belka [17]

Answer:

True;   ar = v^2 / R      Radial acceleration because it moves in a circular path

    at = α R = tangential acceleration because its speed changes

a = at + ar    total acceleration equals sum of radial and tangential

5 0
3 years ago
Sanitation can be accomplished by all of the means except
Nonamiya [84]

Answer:

Air drying

Explanation:

Sanitation is the set of measures that aims to preserve or modify the conditions of the environment in order to prevent diseases and promote health, improve the quality of life of the population and the productivity of the individual and facilitate economic activity. Basic sanitation is a right guaranteed by the Constitution as the set of services, infrastructure and operational installations for water supply, sanitary sewage, urban cleaning, urban drainage, solid waste and rainwater management.

Sanitation can be carried out in several ways, except for dry air, as this would damage the quality of sanitation and the environment.

Sanitation is important in treated water, sewage collection and treatment services lead to an improvement in the quality of people's lives, especially in child health, with a reduction in child mortality, improvements in education, in the expansion of tourism, in the valuation of properties, in income of the worker, in the cleaning of rivers and preservation of water resources, etc.

5 0
4 years ago
What is the electric field due to a point charge of 20uC at a distance of 1 meter away from it?
Anettt [7]

The electric field due to a point charge of 20uC at a distance of 1 meter away from it is 180000 \frac{N}{C}.

First, you have to know that the space surrounding a load suffers some kind of disturbance, since a load located in that space will suffer a force. The disturbance that this charge creates around it is called an electric field.

In other words, an electric field exists in a certain region of space if, when introducing a charge called witness charge or test charge, it undergoes the action of an electric force.

The electric field E created by the point charge q at any point P, located at a distance r, is defined as:

E=K\frac{q}{r^{2} }

where K is the constant of Coulomb's law.

In this case, you know:

  • K= 9×10⁹\frac{Nm^{2} }{C^{2} }
  • q= 20 uC=20×10⁻⁶ C
  • r= 1 m

Replacing in the definition of electric field:

E=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{20x10^{-6} C}{(1 m)^{2} }

Solving:

<u><em>E=180000 </em></u>\frac{N}{C}<u><em /></u>

Finally, the electric field due to a point charge of 20uC at a distance of 1 meter away from it is 180000 \frac{N}{C}.

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5 0
2 years ago
An object is placed a distance of twice the focal length away from a diverging lens. What is the magnification of the image?
Lesechka [4]

Answer:

+1/3

Explanation:

The lens equation states that:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where

f is the focal length

p is the distance of the object from the lens

q is the distance of the image from the lens

For a diverging lens, the focal length is negative: f=-f

and we also know that the object is placed a distance of twice the focal length, so p=2f

So we can find q from the equation above

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{-f}-\frac{1}{2f}=-\frac{3}{2f}\\q=-\frac{2}{3}f

And the magnification of the image is given by

M=-\frac{q}{p}=-\frac{-\frac{2}{3}f}{2f}=\frac{1}{3}

5 0
4 years ago
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