Answer:
1s^2 2s^2 2p^6 3s^1
Explanation:
electron configuration of an element gives description of the distribution of electron in it's orbital of the atom, the superscript symbolize number of electron been hold by them.
The element here is sodium, which is a alkali metal
mass number =23
Number of proton= 11
electron must be seen in thelowest-energy subshell that is available in the the 3s orbital,
Hence, the electronic configuration is
1s^2 2s^2 2p^6 3s^1
Answer:
Mass = 234 g
Explanation:
Given data:
Mass of NaCl produced = ?
Moles of chlorine = 2.0 mol
Solution:
Chemical equation:
2Na + Cl₂ → 2NaCl
now we will compare the moles of NaCl with chlorine gas.
Cl₂ : NaCl
1 : 2
2.0 : 2/1×2.0 = 4.0 mol
Mass of NaCl;
Mass = number of moles × molar mass
Mass = 4.0 mol × 58.5 g/mol
Mass = 234 g
Answer:
1.Most metal oxides are insoluble in water but some of these (e.g. Na2O.
Explanation:
2.: (i) A hissing sound is observed.
1.ii) The mixture starts boiling and lime water is obtained.
You missed a lot of details in your question, so when we have the complete question as the attached picture so, the answer would be:
when we have the value of Ka = 1.8 x 10^-5 so, we can use it to get the Pka value
by using this formula:
Pka = -㏒Ka
= -㏒(1.8 x 10^-5)
= 4.7
now, after we have got the Pka we need now to get moles of NaC2H3O2 and
moles of HC2H3O2:
when moles of NaOH = 0.015 moles
when moles NaC2H3O2 after adding NaOH
= initial mol NaC2H3O2 + mol NaOH
∴moles NaC2H3O2 = 0.1 + 0.015 = 0.115 moles
and moles HC2H3O2 after adding NaOH
= initial mol HC2H3O2 - mol NaOH
∴ moles HC2H3O2 = 0.1 - 0.015 = 0.085 moles
so, when we have moles [HC2H3O2] &[NaC2H3O2] so we can substitution its values in [A] &[HA] :
by using H-H equation we can get the PH:
when PH = Pka + ㏒[A]/[HA] PH = 4.7 + ㏒0.115/0.085
= 4.8
Oceans, they are larger than ponds hence they possess wider exposure with more number of surface molecules.