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Leni [432]
2 years ago
7

i need answers by tonight or the morning. its due tomarrow and im scarred to ask the teacher what to do.

Mathematics
1 answer:
kompoz [17]2 years ago
4 0
I’ll explain part A and you can apply it to the other parts. The functions f(x), g(x), and m(x) are all equivalent to the given polynomials. So when it asks for f(x) + [g(x) - m(x)] you plug them in. The answer to Part A is 3x^2 +5x - z + [5x^2-3x+z - 2x^2 - 2x]. Combine the like terms (3x^2+5x^2-2x^2 = 6x^2 (because 3+5-2=6)) and so on until you’ve simplified it as much as possible!
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PLEASE HELP!!!!!!!!!!!!!!
barxatty [35]

Answer:

Y+m+B=6

Step-by-step explanation:

3 0
2 years ago
If the legs of a right triangle have length of 6 inches and 8 inches, what is the length of the hypotenuse in inches?
Ksju [112]

C. 10

Hope this helps:)

3 0
3 years ago
Read 2 more answers
Please help :(<br> if you can please also give a explanation. thanks
aliina [53]

Answer:

x = 20

Step-by-step explanation:

since the triangle is a right angle, that means the angle is 90 degrees

equation:

30 + 3x = 90

subtract 30 on both sides

30 - 30 + 3x = 90 - 30

3x = 60

then divide each side by 3

\frac{3x}{3} = \frac{60}{3}

x = 20

8 0
2 years ago
City planners are planning to build a new community park. They agree that the park will be rectangular in shape, but the propose
podryga [215]

Answer:

  (c)  714.96 = 21.6(w +4.7)

Step-by-step explanation:

The area of the rectangular park will be the product of its length and width. This relation is used to write an equation to find the original width of the park.

<h3>Width</h3>

Let w represent the original width of the park in meters. The new width is 4.7 meters more, so is represented by (w +4.7).

<h3>Other dimensions</h3>

The length of the park is given as 21.6 meters. The area is given as 714.96 square meters.

<h3>Area formula</h3>

The various dimensions of the park are related by the area formula:

  A = LW

  714.96 = 21.6(w +4.7)

4 0
1 year ago
Colin and amil Each built boxes with a volume of 8 ft.³ Collins box is a cube almils box is a rectangular prism the length of am
SOVA2 [1]

Answer:

4' x 2' x 1'

Step-by-step explanation:

Collins' cube has a volume of that is the length of any side, x, cubed:  Vol = x^3.  Since his box has 8^3, we can say that x = 2.  <u>[2^3 = 8]</u>

Amil's box has one side that is 2x.  That side would be 2*2 = 4 feet.  His volume is also 8 ft^3.  Amil's box also has a volume of 8 ft^3.

His box dimensions are therefore:  (4)(X)(Y) = 8 ft^3 , where X and Y are whole-number dimensions for the other 2 dimensions of his box.

(4)(X)(Y) = 8 ft^3

      X*Y = 2

The only combination of whole numbers for which this this would work is 1 and 2.

Amil's box is 4' x 2' x 1' or 8 ft^3

3 0
2 years ago
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