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m_a_m_a [10]
3 years ago
10

I really need help with this does anybody know how to do this?​

Chemistry
1 answer:
fenix001 [56]3 years ago
8 0

Answer:PLEASE MARK BRAINIEST

The most common method astronomers use to determine the composition of stars, planets, and other objects is spectroscopy. Today, this process uses instruments with a grating that spreads out the light from an object by wavelength. This spread-out light is called a spectrum. Every element — and combination of elements — has a unique fingerprint that astronomers can look for in the spectrum of a given object. Identifying those fingerprints allows researchers to determine what it is made of.

That fingerprint often appears as the absorption of light. Every atom has electrons, and these electrons like to stay in their lowest-energy configuration. But when photons carrying energy hit an electron, they can boost it to higher energy levels. This is absorption, and each element’s electrons absorb light at specific wavelengths (i.e., energies) related to the difference between energy levels in that atom. But the electrons want to return to their original levels, so they don’t hold onto the energy for long. When they emit the energy, they release photons with exactly the same wavelengths of light that were absorbed in the first place. An electron can release this light in any direction, so most of the light is emitted in directions away from our line of sight. Therefore, a dark line appears in the spectrum at that particular wavelength.

Explanation:

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In the experiment "Beer-Lambert’s Law and Spectrophotometry", you prepared a calibration plot similar to the one pictured below.
dexar [7]

Answer:

0.025M

Explanation:

As you must see in your graph, each concentration of the experiment has an absorbance. Following the Beer-Lambert's law that states "The absorbance of a solution is directely proportional to its concentration".

At 0.35 of absorbance, the plot has a concentration of:

<h3>0.025M</h3>
8 0
3 years ago
2. What is the molarity of 100 mL of a 3.0% H2O2 (mass/volume) solution? What is the molarity of 100 mL of a 2.25% H2O2 solution
KatRina [158]

The 3% mass/volume H₂O₂ means 3 g of H₂O₂ in 100 ml of water.

Now, Molarity (M) = No. of moles of H₂O₂ / Volume of solution in liter

No. of moles of H₂O₂ = Mass / Molar mass = 3 g / 34 g/mol = 0.088 mol

So, molarity = 0.088 × 1000 ml / 100 ml = 0.88 M

In case of 2.25 % H₂O₂,

No of moles = 2.25 g / 34 g/mol = 0.066 mol

Molarity = 0.066 mol / 0.100 L = 0.66 M.

7 0
3 years ago
How many valence electrons are in an atom of magnesium?
dimulka [17.4K]
There are two valence electrons in a single atom of magnesium.
8 0
3 years ago
Read 2 more answers
Which statement best describes the properties of sucrose?
crimeas [40]

Answer:

D. They are different from the properties of carbon, oxygen, and hydrogen.  

Step-by-step explanation:

Carbon, oxygen, and hydrogen are all <em>elements. </em>

Sucrose is a <em>compound</em> containing carbon, oxygen, and hydrogen. Its properties are different from those of its elements.

For example, carbon is a <em>black solid,</em> while oxygen and hydrogen are <em>colourless gases</em>. Sucrose is a <em>white solid</em>.

6 0
3 years ago
Read 2 more answers
This is 25 points. Pick any of the 6 questions and show how you did it. I just need to see how you do it and get the answer. You
FromTheMoon [43]
I choose question 1, so molarity is the concentration of a soulution expressed as the number of moles of solute by the litress of soulution. to get molarity you divide the moles of soulute by the litress of solution. soo 1 calculate the number of moles of solute present. 2 Calculate the number of litress solution present. 3. divide the number of moles of solute by the number of litress of solution
soo 1 mol of NaOH has a mass of 40.00 g, so moles of NaOH= 26.7. 1 mole divided 40.00 = 0.375. litress of solution = 650 g. im not sure why its a g i usally do it Ls so i guess its the way your teacher wants you to do it so do you know how to do that. so molarity = moles of solute and litress solution. sorry this probably didnt help i just wanted to add something that might help. im still working on this stuff myself hope this helps.
5 0
3 years ago
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