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m_a_m_a [10]
3 years ago
10

I really need help with this does anybody know how to do this?​

Chemistry
1 answer:
fenix001 [56]3 years ago
8 0

Answer:PLEASE MARK BRAINIEST

The most common method astronomers use to determine the composition of stars, planets, and other objects is spectroscopy. Today, this process uses instruments with a grating that spreads out the light from an object by wavelength. This spread-out light is called a spectrum. Every element — and combination of elements — has a unique fingerprint that astronomers can look for in the spectrum of a given object. Identifying those fingerprints allows researchers to determine what it is made of.

That fingerprint often appears as the absorption of light. Every atom has electrons, and these electrons like to stay in their lowest-energy configuration. But when photons carrying energy hit an electron, they can boost it to higher energy levels. This is absorption, and each element’s electrons absorb light at specific wavelengths (i.e., energies) related to the difference between energy levels in that atom. But the electrons want to return to their original levels, so they don’t hold onto the energy for long. When they emit the energy, they release photons with exactly the same wavelengths of light that were absorbed in the first place. An electron can release this light in any direction, so most of the light is emitted in directions away from our line of sight. Therefore, a dark line appears in the spectrum at that particular wavelength.

Explanation:

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Calculate the equilibrium constant at 25 ∘C for the reaction Fe(s)+2Ag+(aq)→Fe2+(aq)+2Ag(s)
Murrr4er [49]

Answer:

1.7 × 10 ^42

Explanation:

Using Nernst equation

E°cell = RT/nF Inq

at equilibrium

Q=K

E°cell  = 0.0257 /n Ink= 0.0592/n log K

Fe2+(aq)+2e−→Fe(s)     E∘= −0.45 V

Ag+aq)+e−→Ag(s)         E∘= 0.80 V

Fe(s)+2Ag+(aq)→Fe2+(aq)+2Ag(s)

balance the reaction

Fe → Fe²⁺ + 2e⁻  reversing for oxidation E° = 0.45 v

2 Ag⁺ +2e⁻ → 2Ag

n = 2 moles  and K = equilibrium constant

E° cell = 0.80 + 0.45 = 1.25 V

E° cell = (0.0592 / n) log K  

substitute the value into the equations and solve for K

(1.25 × 2) / 0.0592  = log K

42.23 = log K

k = 10^ 42.23

K = 1.7 × 10 ^42

8 0
3 years ago
What is the difference between a homogeneous and heterogeneous mixture?
Semmy [17]
A homogeneous mixture is made up of multiple different substances. (You can see different parts)
Ex: Cereal in milk or ice in soda

A heterogeneous mixture is a mixture that is mixed well. ( you can’t see the different parts)
Ex: Rain or air
8 0
3 years ago
Read 2 more answers
The benedict's test indicates a positive result when the solution turns.
aleksandrvk [35]
it turns yellow to orange
7 0
2 years ago
When baking soda (NaHCO3) is heated, it decomposes, producing carbon dioxide, water, and sodium carbonate. The carbon dioxide is
11Alexandr11 [23.1K]

Answer:

mass of carbon-dioxide = 0.262 g

Explanation:

Firstly, write the chemical equation of the reaction and balance the equation accordingly.

2NaHCO3(aq) → CO2(g) + H2O(l) + Na2CO3(aq)

Calculate the molecular mass of  baking soda

molar mass of baking soda = 23 + 1 + 12 + 48 = 84 g

2 moles of baking soda = 2 × 84 = 168 g

molar mass of CO2 = 12 + 32 = 44 g

if  168 g of baking soda produces 44 g of carbon-dioxide

1 g of baking soda will produce ? grams of carbon-dioxide

cross multiply

mass of carbon-dioxide = 44/168

mass of carbon-dioxide = 0.2619047619

mass of carbon-dioxide = 0.262 g

7 0
3 years ago
Germanium and chlorine react according to the following chemical equation:
seropon [69]

The mass of GeCl4 that would be formed will be 1.51 g

<h3>Stoichiometric calculations</h3>

From the balanced equation of the reaction:

Ge (s) + 2Cl2 (g) →GeCl4

The mole ratio of Ge and Cl2 is 1:2.

Mole of 1.0 g Ge: 1/72.64

                               = 0.01377 mole

Mole of 1.0 g Cl2 = 1/71

                             = 0.01408 mole

Thus, Cl2 is limiting.

Mole ratio of Cl2 and GeCl4 = 2:1

Equivalent mole of GeCl4 = 0.01408/2

                                       = 0.0070 mole

Mass of 0.0070 mole GeCl4 = 0.0070 x 214.4

                                               = 1.51 g

More on stoichiometric calculations can be found here: brainly.com/question/8062886

7 0
2 years ago
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