What is the formula for diarsenic pentoxide

Procaine hydrochloride (MW = 273) is a 2-ion electrolyte, dissociating 80%. Calculate its dissociation factor. Round to tenths p

Inga [223]

Answer:

Dissociation factor = 1.8

Explanation:

Data provided in the question:

Molecular weight of the Procaine hydrochloride = 273

Number of ions contained, n = 2

Fraction Dissociating, α = 80% = 0.8

Now,

the dissociation factor 'i' is given as:

i = 1 + α × ( n - 1 )

on substituting the respective values, we get

i = 1 + 0.8 × ( 2 - 1 )

or

i = 1 + ( 0.8 × 1 )

or

i = 1.8

4 0

4 years ago

How large would the state of New York (235 miles across) be?

Ann [662]

Answer:

235 miles equals 5,280 feet

Explanation:

7 0

3 years ago

What depends on public opinion and support? A. regulations at a local level B. enforcement of laws C. success of a policy D. rev

Nastasia [14]

i believe the answer is success of a policy. if this was correct please mark brainliest and lmk if you have any more questions x

3 0

4 years ago

Use the following equation to answer the questions and please show all work.

DIA [1.3K]

Answer:

a.36 g of water is produced.

b.64 g of $O_{2}$ is consumed.

Explanation:

The reaction is $2H_{2} + O_{2}$ ⇒ $2H_{2}O$

a.

Given,

Weight of $H_{2}$ reacted = 4g

Weight of 1 mole of $H_{2}$ = 2 $\times$ 1 = 2g

Therefore no. of moles of $H_{2}$ reacted = $\frac{4}{2}$ = 2 moles;

Also given,

Weight of $O_{2}$ reacted = 32 g

Weight of 1 mole of $O_{2}$ = 2 $\times$ 16 = 32 g

Therefore no. of moles of $O_{2}$ reacted = $\frac{32}{32}$ = 1

We know that 2 moles of Hydrogen reacts with 1 mole of Oxygen to give 2 moles of water,

As we took 2 moles of Hydrogen and 1 mole of Oxygen,

Directly,from the equation we can tell 2moles of water will be produced.

Therefore no. of moles of $H_{2} O$ produced = 2

Weight of 1 mole of water = $2\times 1+16$ = 18

Therefore weight of $H_{2}O$ produced = $2\times 18$ = 36gm

b.

Given ,

72 g of $H_{2}O$ is produced.

So,

no. of moles of $H_{2}O$ produced = $\frac{72}{18}$ = 4 moles

From equation For every 2 moles of water formed , 1 mole of oxygen must be required.

So for producing 4 moles of water,

No. of moles of Oxygen required = 2 moles.

Therefore weight of $O_{2}$ reacted = $2\times32$ = 64 g

Method 2:

Given,

8 g of $H_{2}$ has reacted.

So,

no. of moles of $H_{2}$ reacted = $\frac{8}{2}$ = 4 moles.

From equation , we know that For every 2 moles of $H_{2}$ reacted,1 mole of $O_{2}$ will react.

Therefore,

No. of moles of $O_{2}$ that reacts with 4 moles of $H_{2}$ = $2\times1$ = 2 moles

Therefore the weight of $O_{2}$ reacted = $2\times 32$ = 64 g

6 0

3 years ago

What is the most likely way a chemist would be involved in the production of<br> a computer chip?

ZanzabumX [31]

Answer: Computer chips are very complex, maybe there are things insode that chemists are familiar with. Maybe they can give insight about this.

Explanation:

4 0

3 years ago