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prisoha [69]
3 years ago
15

if the spin of one electron in an orbital is clockwise , what is the spin of the other electron in that orbital

Chemistry
1 answer:
nata0808 [166]3 years ago
6 0

Here we have to get the spin of the other electron present in a orbital which already have an electron which has clockwise spin.

The electron will have anti-clockwise notation.

We know from the Pauli exclusion principle, no two electrons in an atom can have all the four quantum numbers i.e. principal quantum number (n), azimuthal quantum number (l), magnetic quantum number (m) and spin quantum number (s) same. The importance of the principle also restrict the possible number of electrons may be present in a particular orbital.

Let assume for an 1s orbital the possible values of four quantum numbers are n = 1, l = 0, m = 0 and s = \frac{+}{-}\frac{1}{2}.

The exclusion principle at once tells us that there may be only two unique sets of these quantum numbers:

1, 0, 0, +\frac{1}{2} and 1, 0, 0, -\frac{1}{2}.

Thus if one electron in an orbital has clockwise spin the other electron will must be have anti-clockwise spin.    

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How many molecules of CaCi2 are equivalent to 75.9 grams
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6,02·10²³ molecules ---------- 111g
X molecules --------------------- 75,9g
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:)
8 0
3 years ago
What is the solution to the problem expressed to the correct number of significant figures? 2.13 + 1 = ?
Paha777 [63]

So,

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We know 2.13 to the hundredths, but we only know 1 to the ones.  Therefore, we will round off in the ones place.

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Hope this helps!

7 0
3 years ago
when a number in scientific notation contains a significant zero, is that zero also significant in the expanded notation? give t
AlexFokin [52]
I believe you are referring zero as the exponent. <span>Any number (except 0) with exponent 0 is defined to mean 1.
</span>

For one thing, there is a rule: 

<span> a^m/ a^m = a^m-m = a^0

</span>But (when a is not equal to <span>0),
</span>
a^m/ a^m = 1

Therefore, we must define a^0 as 1.

4 0
3 years ago
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