Answer:
how can I solve this ?4Al+3O2 produce 2Al2O3 find a) oxygen atoms needed to react with 5.4 g of aluminium b) grams of oxygen needed to react with 0.6 mol of aluminium?
(A) n=m/M,
n(Al)=5.4/27=0.2 moles
n(O2)=n(Al)*3/4=0.2*3/4=0.15 moles
Number of oxygen atoms= n(O2)*Avogadro's number
=0.15*6.02*10^23=9.03*10^22 oxgyen atoms
(B)
n=m/M
n(Al)=0.6/27=0.02222 moles
n(O2)=n(Al)*3/4=0.016666 moles
m=n*M
m(O2)=0.0166666*32=0.53333 grams
Answer:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁶
Explanation:
Iron is soft, bright white metal.
Its symbol is Fe, atomic number is 26 and atomic mass is 55.85 amu.
It is present in group 8 of periodic table.
It is used to make the steel.
It is malleable and ductile used to make the sheets.
It is good conductor of heat and electricity because of moveable electrons that can easily move from one to another atom.
Its density is 7.87 g/cm³.
Electronic configuration:
Fe₂₃ = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁶
Abbreviated electronic configuration:
Fe₂₃ = [Ar] 3d⁶4s²