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prisoha [69]
2 years ago
15

if the spin of one electron in an orbital is clockwise , what is the spin of the other electron in that orbital

Chemistry
1 answer:
nata0808 [166]2 years ago
6 0

Here we have to get the spin of the other electron present in a orbital which already have an electron which has clockwise spin.

The electron will have anti-clockwise notation.

We know from the Pauli exclusion principle, no two electrons in an atom can have all the four quantum numbers i.e. principal quantum number (n), azimuthal quantum number (l), magnetic quantum number (m) and spin quantum number (s) same. The importance of the principle also restrict the possible number of electrons may be present in a particular orbital.

Let assume for an 1s orbital the possible values of four quantum numbers are n = 1, l = 0, m = 0 and s = \frac{+}{-}\frac{1}{2}.

The exclusion principle at once tells us that there may be only two unique sets of these quantum numbers:

1, 0, 0, +\frac{1}{2} and 1, 0, 0, -\frac{1}{2}.

Thus if one electron in an orbital has clockwise spin the other electron will must be have anti-clockwise spin.    

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A thermally isolated system is made up of a hot piece of aluminum and a cold piece of copper; the aluminum and the copper are in
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Answer:

  • <u>Copper</u><em> is the object that experiences the greater temperature change.</em>

Explanation:

<em>Thermally isolated system </em>means that the system does not exchange thermal energy with the surroundings.

Hence, any thermal exchange, in virtue of the temperature difference of the aluminum and copper pieces, is between them.

In consequence, the law of conservation of energy states that the heat lost by the hot substance will be gained by the cold matter.

In equations, that is:

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Now, the gain or loss or heat of a substance, Q, is related with the mass (m), the specific heat (Cs), and the cahnge of temperature (ΔT), per the equation:

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∴ Q lost by aluminum = Q  gained copper ⇒

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Under the reasoning assumption that the masses of aluminum and copper are equal, the equations is simplified to:

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  • Cs aluminum / Cs copper = ΔT copper / ΔT aluminum

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In words, since it is stated that  the specific heat of aluminum is more than double that of copper,  in order to keep the equality, ΔT of copper shall be more than double ΔT of aluminum.

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3 years ago
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Answer:

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