Question

PLEASE HELP!!! Find the real number solutions for the equation. x^2 - 3x + 8 = 0

Answer 1

To find the real number solutions for the equation, we need to use the quadratic formula:
$x = \frac{ - b( + - ) \sqrt{ {b}^{2} - 4ac } }{2a}$
(pardon the (+-), it is supposed to be a plus/minus sign) from the equation
$a {x}^{2} + bx + c$
In this case, we have a = 1, b = -3, c = 8.
$- ( - 3)$
$\frac{ - ( - 3)( + - ) \sqrt{ {( - 3)}^{2} - 4(1)(8) } }{4(1)} \\ \frac{3( + - ) \sqrt{9 - 36} }{4}$
Since 9 - 36 is a negative number and we cannot square root a negative number, the answer is D. Cannot be determined.

Answer 2

$x^{2} -3x+8=0$

$\Delta= 3^{2} -4*8*1=9-32=-23\ \textless \ 0$

Answer D 
Cannot be determined