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lakkis [162]
3 years ago
9

A certain bank offers a car loan with a fixed annual interest rate. Justine applied for the loan and used the entire amount to b

uy a car worth $43,000. He had to pay the bank for five years for a total amount of $51,600. How much would be the yearly interest if Justine borrowed $50,000 instead? *
0 points
Mathematics
1 answer:
natita [175]3 years ago
8 0

Answer: $10000

Step-by-step explanation:

From the question,

Principal = $43000

Time = 5 years

Rate = Unknown

Simple Interest = $51,600 - $43000 = $8600

We need to calculate the rate of interest which will be:

Interest = PRT/100

8600 = (43000 × 5 × Rate) / 100

Cross multiply

8600 × 100 = 215000 × Rate

Rate = 860000 / 215000

Rate = 4%

Assuming Justine borrowed $50,000 instead, the yearly Interest will be:

= (50000 × 5 × 4%)

= 50000 × 5 × 0.04

= $10000

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Say a hacker has a list of n distinct password candidates, only one of which will successfully log her into a secure system. a.
alexdok [17]

Answer:

The probability is \frac{1}{n}

Step-by-step explanation:

If she has n distinct password candidates and only one of which will successfully log her into a secure system, the probability that her first first successful login will be on her k-th try is:

If k=1

P = \frac{1}{n}

Because, in her first try she has n possibles options and just one give her a successful login.

If k=2

P=\frac{n-1}{n} *\frac{1}{n-1} =\frac{1}{n}

Because, in her first try she has n possibles options and n-1 that are not correct, then, she has n-1 possibles options and 1 of that give her a successful login.

If k=3

P=\frac{n-1}{n} *\frac{n-2}{n-1} *\frac{1}{n-2} = \frac{1}{n}

Because, in her first try she has n possibles options and n-1 that are not correct, then, she has n-1 possibles options and n-2 that are not correct and after that, she has n-2 possibles options and 1 give her a successful login.

Finally, no matter what is the value of k, the probability that her first successful login will be (exactly) on her k-th try is 1/n

7 0
3 years ago
Kyle mixes 45 grams of popcorn with 15 grams of powdered cheese. How much popcorn does Kylebuse per gram of cheese?
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Answer:

B

Step-by-step explanation:

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15 POINTS!!! HELP ASAP!! What are the domain and range of the function graphed below?
aleksklad [387]

Answer:

C. domain: {x ≤ 2}; range: {–∞ < y < ∞}

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3 years ago
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Alenkasestr [34]

Answer:

μ =  Sin θ * d₁ / (d₂ - Cos θ*d₁)

d₂ = (d₁*Sin θ) / μ

Step-by-step explanation:

a) We apply The work-energy theorem

W = ΔE

W = - Ff*d

Ff = μ*N = μ*m*g

<em>Distance 1:</em>

- Ff*d₁ = Ef - Ei

⇒  - (μ*m*g*Cos θ)*d₁ = (Kf+Uf) - (Ki+Ui) = (Kf+0) - (0+Ui) = Kf - Ui

Kf = 0.5*m*vf² = 0.5*m*v²

Ui = m*g*h = m*g*d₁*Sin θ

then

- (μ*m*g*Cos θ)*d₁ = 0.5*m*v² - m*g*d₁*Sin θ  

⇒   - μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ   <em>(I)</em>

 

<em>Distance 2:</em>

<em />

- Ff*d₂ = Ef - Ei

⇒  - (μ*m*g)*d₂ = (0+0) - (Ki+0) = - Ki

Ki = 0.5*m*vi² = 0.5*m*v²

then

- (μ*m*g)*d₂ = - 0.5*m*v²

⇒   μ*g*d₂ = 0.5*v²     <em>(II)</em>

<em />

<em>If we apply (I) + (II)</em>

- μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ

μ*g*d₂ = 0.5*v²

 ⇒ μ*g (d₂ - Cos θ*d₁) = v² - g*d₁*Sin θ   <em>  (III)</em>

Applying the equation (for the distance 1) we get v:

vf² = vi² + 2*a*d = 0² + 2*(g*Sin θ)*d₁   ⇒   vf² = 2*g*Sin θ*d₁ = v²

then (from the equation <em>III</em>) we get

μ*g (d₂ - Cos θ*d₁) = 2*g*Sin θ*d₁ - g*d₁*Sin θ

⇒  μ (d₂ - Cos θ*d₁) = Sin θ * d₁

⇒   μ =  Sin θ * d₁ / (d₂ - Cos θ*d₁)

b)

If μ is a known value

d₂ = ?

We apply The work-energy theorem again

W = ΔK   ⇒   - Ff*d₂ = Kf - Ki

Ff = μ*m*g

Kf = 0

Ki = 0.5*m*v² = 0.5*m*2*g*Sin θ*d₁ = m*g*Sin θ*d₁

Finally

- μ*m*g*d₂ = 0 - m*g*Sin θ*d₁   ⇒   d₂ = Sin θ*d₁ / μ

3 0
3 years ago
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Tema [17]

Answer:

5x^2-12x-2

Step-by-step explanation:

Use distributive property, then add like terms. See file below for steps.

4 0
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