1 year ago

The car took 2 hours 15 minutes to travel 190 km . if it arrived at its destination at 12:06 . find the average speed of car

Mathematics

1 answer:

a_sh-v [17]1 year ago

7 0

Answer:

23.46

$m {s}^{ - 1}$

Step-by-step explanation:

I am attaching a photo.

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8_murik_8 [283]

Answer:

1. terms: 4r, 2, -6, and 3r like terms: 2 and -6, 4r and 3r

2.terms: 5h^2, -3h^2, - 4h, 3h, 7 like terms: 5h^2 and -3h^2, - 4h and 3h

3. 3m + 6

4. 15b + 2

5. 3x + 9

Step-by-step explanation:

1. 4r + 2 - 6 +3r

terms: 4r, 2, -6, and 3r like terms: 2 and -6, 4r and 3r

2. 5h^2 - 3h^2 - 4h + 3h + 7

terms: 5h^2, -3h^2, - 4h, 3h, 7 like terms: 5h^2 and -3h^2, - 4h and 3h

3. 6m + 7 - 3m-1

3m + 6

4. 3(5b +2) - 4

15b + 6 - 4

15b + 2

5. 2x + 4 + 5 + x

3x + 9

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3 years ago

Area of a rectangle with sides measuring 34.5 and 45.3 feet

MariettaO [177]

Answer:

1,562.85

Step-by-step explanation:

34.5 times 45.3

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2 years ago

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liubo4ka [24]

Answer:

Option A

Step-by-step explanation:

<u>Given equation is:</u>

$x^2+1=2x-3$

Setting it up as a quadratic equation.

$x^2+1-2x+3=0\\\\x^2-2x+4=0$

Comparing it with quadratic equation $ax^2+bx+c=0$ , we get:

a = 1 , b = -2 , c = 4

<u>Putting the values in quadratic equation:</u>

$\displaystyle x = \frac{-b +-\sqrt{b^2-4ac} }{2a} \\\\x = \frac{-(-2)+-\sqrt{(-2)^2-4(1)(4)} }{2(1)}$

$\rule[225]{225}{2}$

Hope this helped!

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2 years ago

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