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wel
3 years ago
9

If sinA= 3/4 find. (a) tanA (b):cosA. (c):sinA cosA+tanA/3+4cosA tanA​

Mathematics
1 answer:
Luba_88 [7]3 years ago
3 0

here is your answer. Please like it rate it and mark me as brainly.

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Blediana read a total of 10 Harry Potter books over 5 months. After belonging to the book club for 6 months, how many books will
attashe74 [19]
Blediana would have read a total of 12 Harry Potter books in 6 months. 
If she read 10 books in 5 months, that would be 2 books per month. 6 months would allow her to lead a total of 12 books.
4 0
3 years ago
vRichard has a red card (R) and a black card (B). He picks a card randomly from the pair and then rolls a six-sided die. The sam
Alik [6]

The Sample space for three cards is

S=\left\{\left(B,1\right),\left(R,1\right),\left(G,1\right),\left(B,2\right),\left(R,2\right),\left(G,2\right),\left(B,3\right),\left(R,3\right),\left(G,3\right),\left(B,4\right),\left(R,4\right),\left(G,4\right)\left(B,5\right),\left(R,5\right),\left(G,5\right),\left(B,6\right),\left(R,6\right),\left(G,6\right) \right \}

There are two cards red(R) and black(B) and a six-sided die.

The event is one card is picked randomly and then rolls the die.

So, the Sample space is as follows.

S=\left\{\left(B,1\right),\left(R,1\right),\left(B,2\right),\left(R,2\right),\left(B,3\right),\left(R,3\right),\left(B,4\right),\left(R,4\right),\left(B,5\right),\left(R,5\right),\left(B,6\right),\left(R,6\right) \right \}

<h3>Find Sample space if there are three cards.</h3>

Consider there were three cards red(R), black(B) and green(G) a six-sided die.

The event is one card is picked randomly and then rolls the die.

So, the sample space will be as follows,

S=\left\{\left(B,1\right),\left(R,1\right),\left(G,1\right),\left(B,2\right),\left(R,2\right),\left(G,2\right),\left(B,3\right),\left(R,3\right),\left(G,3\right),\left(B,4\right),\left(R,4\right),\left(G,4\right)\left(B,5\right),\left(R,5\right),\left(G,5\right)\left(B,6\right),\left(R,6\right),\left(G,6\right) \right \}.

Learn more about sample space here :-

brainly.com/question/24273864

#SPJ1

7 0
2 years ago
The PE class has 12 boys and 8 girls. What is the maximum number of teams that the teacher can divide the class into so that eac
Ugo [173]

Answer:

B. 4

Step-by-step explanation:

The maximum number of teams the teacher can divide the class into is 4. I got it right on ED2020.

6 0
4 years ago
Read 2 more answers
Each item produced by a certain manufacturer is independently of acceptable quality with probability 0.95. Approximate the proba
Diano4ka-milaya [45]

Answer:

The probability that at most 10 of the next 150 items produced are unacceptable is 0.8315.

Step-by-step explanation:

Let <em>X</em> = number of items with unacceptable quality.

The probability of an item being unacceptable is, P (X) = <em>p</em> = 0.05.

The sample of items selected is of size, <em>n</em> = 150.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 150 and <em>p</em> = 0.05.

According to the Central limit theorem, if a sample of large size (<em>n</em> > 30) is selected from an unknown population then the sampling distribution of sample mean can be approximated by the Normal distribution.

The mean of this sampling distribution is: \mu_{\hat p}= p=0.05

The standard deviation of this sampling distribution is: \sigma_{\hat p}=\sqrt{\frac{ p(1-p)}{n}}=\sqrt{\frac{0.05(1-.0.05)}{150} }=0.0178

If 10 of the 150 items produced are unacceptable then the probability of this event is:

\hat p=\frac{10}{150}=0.067

Compute the value of P(\hat p\leq 0.067) as follows:

P(\hat p\leq 0.067)=P(\frac{\hat p-\mu_{p}}{\sigma_{p}} \leq\frac{0.067-0.05}{0.0178})=P(Z\leq 0.96)=0.8315

*Use a <em>z</em>-table for the probability.

Thus, the probability that at most 10 of the next 150 items produced are unacceptable is 0.8315.

5 0
3 years ago
What is the product of (-6)(-7)(-1)?<br> o42<br> О —14<br> ООО
astra-53 [7]

Answer:

The product is -42.

Step-by-step explanation:

This is because (-6)(-7)= 42 and (42)(-1)= -42

3 0
3 years ago
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