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Alexxx [7]
3 years ago
5

What kind of relationship exists between the hours a person spend at work in the hours they spend at home positive negative or n

one
Mathematics
1 answer:
joja [24]3 years ago
8 0
Mhhhhhhhhhhhhhhhhhhhhhhhhhh
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I think it’s 24 I could be wrong but I’m pretty sure
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Y=4x+1 complete the table
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<em>Please</em><em> </em><em>refer</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>image</em><em> </em><em>for</em><em> </em><em>the</em><em> </em><em>answer</em>

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2 years ago
Find the value of X.
iris [78.8K]

Answer:

Step-by-step explanation:

90 + 122 + 4x + 19 + 9x - 8 + 7x - 3 = 540

220 + 20x = 540

-220             -220

--------------------------

20x = 320

/20     /20

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2 years ago
Which expression is equivalent to...
torisob [31]

Answer:

x^{\frac{2}{7} } y^{-\frac{3}{5} } \\  i.e answer A.

Step-by-step explanation:

This question involves knowing the following power/exponent rule:

\sqrt[n]{x^m} = x^\frac{m}{n} \\\\so \sqrt[7]{x^2} = x^\frac{2}{7} \\\\and  \\\\ \sqrt[5]{y^3} = y^\frac{3}{5} \\

Next, when a power is on the bottom of a fraction, if we want to move it to the top, this makes the power become negative.

so the y-term, when moved to the top of the fraction, becomes:

y^{-\frac{3}{5} } \\

So the answer is: x^{\frac{2}{7} } y^{-\frac{3}{5} } \\

7 0
2 years ago
What is the distance covered by a train while slowing down from
alukav5142 [94]

Answer:

The distance covered is 113.75 m

Step-by-step explanation:

As per the question:

The initial velocity of the train, v = 20 m/s

The final velocity of the train, v' = 6 m/s

Uniform deceleration, a = 1.6m/s^{2}

Or uniform acceleration, a = - 1.6m/s^{2}

<em>Here, the body decelerates, i.e., slows down at a uniform rate thus we take acceleration with negative sign.</em>

Now, to find the distance covered, s:

Using the eqn of Kinemetics:

v'^{2} = v^{2} + 2as

6^{2} = 20^{2} + 2(- 1.6)s

36 - 400 = - 3.6s

s = \frac{- 364}{- 3.6} = 113.75\ m

5 0
3 years ago
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