Option C
For each value of y, -2 is a solution of -21 = 6y - 9
<u>Solution:</u>
Given, equation is – 21 = 6y – 9
We have to find that whether given set of options can satisfy the above equation or not
Now, let us check one by one option
<em><u>Option A) </u></em>
Given option is -5
Let us substitute -5 in given equation
- 21 = 6(-5) – 9
- 21 = -30 – 9
- 21 = - 39
L.H.S ≠ R.H.S ⇒ not a solution
<em><u>Option B)</u></em>
Given option is 3
- 21 = 6(3) – 9
- 21 = 18 – 9
- 21 = 9
L.H.S ≠ R.H.S ⇒ not a solution
<em><u>Option C)</u></em>
Given option is -2
- 21 = 6(-2) – 9
- 21 = - 12 – 9
- 21 = - 21
L.H.S = R.H.S ⇒ yes a solution
<em><u>Option D)</u></em>
- 21 = 6(9) – 9
- 21 = 54 – 9
- 21 = 45
L.H.S ≠ R.H.S ⇒ not a solution
Hence, the solution for the given equation is – 2, so option c is correct
Answer:
Length: x + 5
Step-by-step explanation:
x² + 8x + 15 = length × width
x² + 8x + 15
x² + 5x + 3x + 15
x(x + 5) + 3(x + 5)
(x + 5)(x + 3)
Width: (x + 3)
Length: (x + 5)
Answer:
<h2>ratio is </h2>
Step-by-step explanation:
<h2>2:7. your answer is like. </h2>
<h2>Follow me</h2>
Answer:
C. 5√3
Step-by-step explanation:
To figure this out, we need to apply the Pythagorean Theorem, <em>a</em><em>²</em><em> </em><em>+</em><em> </em><em>b</em><em>²</em><em> </em><em>=</em><em> </em><em>c</em><em>²,</em><em> </em>where <em>c</em><em> </em>is the "HYPOTENUSE". In this case, <em>c</em><em> </em>is already found for us [10], so the operation we use whenever the hypotenuse is defined is deduction, or subtraction. Apply the Pythagorean Theorem: a² + 25 = 100; 75 = a². Now, to find <em>a</em><em>,</em><em> </em>we need to find two numbers that multiply to 75, where one of them is a PERFECT SQUARE, and in this case, they are 3 and 25. Since the square root of 25 is 5 [in this case, NO NON-NEGATIVE root], that gets moved to the outside of the radical, and 3 [NON-PERFECT SQUARE] stays wrapped under the radical, ending up with <em>5</em><em>√</em><em>3.</em><em> </em>You understand?
I am joyous to assist you anytime.
