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Setler [38]
3 years ago
10

Question 3 of 5

Chemistry
1 answer:
rusak2 [61]3 years ago
7 0

Answer:

A. More mass

C. Shorter distance between them

Explanation:

The two characteristics of a body experiencing greater gravitational force are that they have mass and a shorter distance between them.

This is conformity with Newton's law of universal gravitation.

The law states that "every object attracts one another with a force that is directly proportional to their masses and inversely proportional to the square of the distance between them".

This law implies that the more the mass of two bodies, the more the gravitational force of attraction. And that the shorter the square of the distance between them, the more the attraction.

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Which statement about Niels Bohr's atomic model is true?
cupoosta [38]

Answer:

o

Explanation:

6 0
3 years ago
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Write the following numbers in scientific notation: a) 0.0006730 b)50000.0 c)0.000003010 d) 132.40 e)2232​
Firdavs [7]

Answer:

a)6.730×10⁻⁴

b)5×10⁴

c)3.010×10⁻⁶

d)1.3240×10²

e)2.232×10³

3 0
3 years ago
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What is the chemical formula for marble?
Maru [420]

Calcium carbonate is <span>marble.
CaCo</span>₃ is marble.
7 0
4 years ago
A certain substance X has a normal freezing point of -6.4 C and a molal freezing point depression constant Kf= 3.96 degrees C.kg
Brut [27]

Answer:  1.0\times 10^2g

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=(-6.4-(13.6))^0C=7.2^0C = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte like urea)

K_f = freezing point constant = 3.96^0C/m

m= molality

\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}}\times \text{weight of solvent in kg}}

Weight of solvent (X)= 950 g = 0.95 kg  

Molar mass of non electrolyte (urea) = 60.06 g/mol

Mass of non electrolyte (urea) added = ?

7.2=1\times 3.96\times \frac{xg}{60.06 g/mol\times 0.95kg}

x=1.0\times 10^2g

Thus 1.0\times 10^2g urea was dissolved.

8 0
4 years ago
How many grams of KNO3 are present in 185 mL of a 2.50 M solution?
stepan [7]

Answer:

46.71g

Explanation:

First, we'll begin by calculating the number of mole of KNO3 present in the solution. This is illustrated below below:

Data obtained from the question:

Molarity = 2.50 M

Volume = 185 mL = 185/1000 = 0.185L

Mole =?

Molarity = mole /Volume

Mole = Molarity x Volume

Mole = 2.5 x 0.185

Mole = 0.4625 mole

Now we can obtain the mass of KNO3 as follow:

Molar Mass of KNO3 = 39 + 14 + (16x3) = 39 + 14 + 48 = 101g/mol

Number of mole of KNO3 = 0.4625 mole

Mass of KNO3 =?

Mass = number of mole x molar Mass

Mass of KNO3 = 0.4625 x 101

Mass of KNO3 = 46.71g

6 0
3 years ago
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