Question

The general form of an interval estimate of a population mean or population proportion is the _____ plus and minus the _____. level of significance, degrees of freedom point estimate, margin of error planning value, confidence coefficient population mean, standard error

Answer 1

Answer:

The confidence interval for the mean is given by the following formula:  

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

Where :

$\hat p$ represent the point of estimate

And $ME = z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ represent the margin of error

For this reason the confidence interval is the point of estimates plus/minus the margin of error

D.) ​point estimate, margin of error

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The confidence interval for the mean is given by the following formula:  

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

Where :

$\hat p$ represent the point of estimate

And $ME = z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ represent the margin of error

For this reason the confidence interval is the point of estimates plus/minus the margin of error

D.) ​point estimate, margin of error