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zavuch27 [327]
2 years ago
7

A rocket moves at the speed of 4.9 miles per second. How fast is the rocket traveling kilometers/hour (km/h)? (1 mile = 1.6 kilo

meter)
A.) 0.0008 km/h
B.) 0.0022 km/h
C.) 11,025 km/h
D.) 28,224 km/h
Mathematics
2 answers:
alexira [117]2 years ago
8 0
The answer is c) 11,025 km/h
Airida [17]2 years ago
4 0

First, we convert the seconds to hours

1 hour = 60 minutes = 60 * 60 seconds = 3,600 seconds

1 hour has 3,600 seconds

If the rocket moves 4.9 miles in a second, in 3,600 seconds , it moves = 3,600*4.9 = 17,640 miles

So, in 1 hour the rocket moves 17,640 miles.

We have been given that 1 mile = 1.6 kilometers

So, 17,640 miles = 17,640*1.6 = 28,224 kilometers

So the rocket moves at a speed of 28,224 kilometers/hour


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Answer:

B. (1,5) and (5.25, 3.94)

Step-by-step explanation:

The answer is where the 2 equations intersect.

We need to solve the following system of equations:

y = -x^2 + 6x

4y = 21 - x

From the second equation:

x = 21 - 4y

Plug this into the first equation:

y = -(21 - 4y)^2 + 6(21 - 4y)

y = -(441 - 168y + 16y^2)+  126 - 24y

y = -441 + 168y - 16y^2 +  126 - 24y

16y^2 + y - 168y + 24y + 441 - 126 = 0

16y^2 - 143y + 315 = 0

y = [-(-143) +/- sqrt ((-143)^2 - 4 * 16 * 315)]/ (2*16)

y = 5, 3.938

When y = 5:

x = 21 - 4(5) = 1

When y = 3.938

x = 21 - 4(3.938) = 5.25.

3 0
3 years ago
Find the value of x and y
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Answer:

Step-by-step explanation:

OS ≅ OU, so we will set those 2 expressions equal to each other and solve for y:

6y = 42 so

y = 7

Same goes for OT and OV:

x + 5 = 23 so

x = 18 and

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5 0
3 years ago
Paul’s grandmother gave him a collection of 30 coins. Each month Paul adds 5 coins to his collection. Which inequality can be us
Elodia [21]

Answer:

B

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  • He starts out with 30
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  • x represents the number of months

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3 0
2 years ago
Evaluate 20/6 - 2/3. 2 1/6, 2 2/3, 3 1/3, 3 2/3
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Answer:

Step-by-step explanation:

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7 0
2 years ago
Which expression is equivalent
gtnhenbr [62]

Answer:

Option  B is correct.

\frac{81m^2n^5}{8} is equivalent to \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Step-by-step explanation:

Given expression: \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Using exponents power:

  • (ab)^n = a^nb^n
  • (a^n)^m = a^{nm}
  • a^m \cdot a^n = a^{m+n}

Given: \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}

Apply exponent power :

⇒ \frac{3^4 (m^{-1})^4(n^2)^4}{2^3(m^{-2})^3 n^3}

⇒ \frac{81 m^{-4}n^8}{8m^{-6}n^3} = \frac{81 m^{-4} \cdot m^6 n^8 \cdot n^{-3}}{8}

⇒\frac{81 m^{-4+6} n^{8-3}}{8} = \frac{81 m^2 n^5}{8} = \frac{81m^2 n^5}{8}

Therefore, the expression which is equivalent to  \frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3} is,  \frac{81m^2 n^5}{8}

4 0
3 years ago
Read 2 more answers
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