2 years ago

(w^3)^3 -geometry need help please

Mathematics

1 answer:

erik [133]2 years ago

6 0

It should be W^9 , no parenthesis

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Graph the equation

Lisa [10]

To find the root, replace y with 0
X^2-12x+35=0
A=1 B=-12 C=35
B^2-4ac=(-12)^2 -4(1)(35)
=144 -140
=4

x=(-b+/- square root of b^2 -4ac) /over/ (2a)
Plug in the numbers
x=-(-12) sqr (-12)^2 4(1)(35) / (2)(1)
X=12 +/-sqr 4 / 2
Positive outcome
x=12 + sqr 4 / 2
x=12+2/2
x=7 <— this one
Negative outcome
x=12-2i/2
x=6-i
Vertex: (6,-1)

8 0

2 years ago

If EFGH is a rectangle, what is FH?

lys-0071 [83]

I believe FH would be a line segment.
Hope this helps!

3 0

2 years ago

Thank you now help please

swat32

If it is #17 this:

the class sold 45 sandwiches and collected $150.75, all you need to do is divide.

150.75/45
= 3.35

$3.35 per sandwitch

4 0

2 years ago