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3 years ago

Find the value of x. PLEASE HELP!!!!

Mathematics

1 answer:

Diano4ka-milaya [45]3 years ago

4 0

Answer:

Step-by-step explanation:

Because of the right angle (90 deg) in red, and the horizontal line on the bottom axis,

we know that :

49 + (1+5x) = 90

solving for x delivers x=8

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Dana buys dress shirts from a clothing manufacturer for s dollars each, and then sells the dress shirts in her retail clothing s

Lerok [7]

Answer:

.35s=p

Step-by-step explanation:

s is the amount she pays

.35 is the amount she marks up

p is profit

7 0

3 years ago

There are 59 boys and 49 girls in this year's baseball league. If the league has nine teams how many players will be on each tea

liraira [26]

Answer: There are 12 players in each team.

Step-by-step explanation:

Since we have given that

Number of boys in this year's baseball league = 59

Number of girls in this year's baseball league = 49

Total number of players in altogether is given by

$59+49=108$

Now, there are 9 teams in the league ,

So,

$\text{Number of players in each team}=\frac{108}{9}=12$

Hence, there are 12 players in each team.

8 0

3 years ago

Please help me with this it is hard for me but not for my seniors First person with correct answer gets Brainliest answer.

kifflom [539]

Answer:

Step-by-step explanation:

a. 2x + 36

2. 6a + 15b

3. 35x + 15y

4. 3p + 2q

5. 3a + 8

3 0

2 years ago

A package of 10 batteries is checked to determine if there are any dead batteries. Four batteries are checked. If one or more ar

frutty [35]

Answer:

There is a probability of 76% of not selling the package if there are actually three dead batteries in the package.

Step-by-step explanation:

With a 10-units package of batteries with 3 dead batteries, the sampling can be modeled as a binomial random variable with:

n=4 (the amount of batteries picked for the sample).
p=3/10=0.3 (the proportion of dead batteries).
k≥1 (the amount of dead batteries in the sample needed to not sell the package).

The probability of having k dead batteries in the sample is:

$P(x=k) = \dbinom{n}{k} p^{k}q^{n-k}$

Then, the probability of having one or more dead batteries in the sample (k≥1) is:

$P(x\geq1)=1-P(x=0)\\\\\\P(x=0) = \dbinom{4}{0} p^{0}q^{4}=1*1*0.7^4=0.2401\\\\\\P(x\geq1)=1-0.2401=0.7599\approx0.76$

8 0

3 years ago

Use scientific notation to rewrite the number:

slavikrds [6]

A. 2.603*10^-4
b. 538

3 0

2 years ago

Read 2 more answers