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2 years ago

Simplify 7N - 2N + 3P + 2P. (a) 5N + 5P (b) 10N + 10P (c)10NP

2 answers:

7 0

<span>7N - 2N + 3P + 2P

Combine like terms:
7N-2N=5N

3P+2P=5P

Put them together to get :
5N+5P

Final answer:
A</span>

aleksklad [387]2 years ago

3 0

I believe the answer to your question is 5N + 5P. I apologize in advance if the answer I gave you is incorrect.

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Given ∆ABC with vertices A(−4, −3), B(0, 0), C(2, −3) and ∆DEF with vertices D(3, 1), E(6, -3), F(3, −5), use the definition of

dimaraw [331]

By SSS congruency criteria ΔABC ≅ ΔDEF

<h3>What is congruency?</h3>

Two figures or objects are congruent if they have the same shape and size, or if one has the same shape and size as the mirror image of the other.

The given vertices of the triangles are;

ΔABC: A(−4, −3), B(0, 0), C(2, −3)

ΔDEF: D(3, 1), E(6, -3), F(3, −5)

The lengths of the sides of ΔABC are

AB = √((0+4)² + (0+3)²) = √25 = 5

BC = √((2-0)² + (-3 - 0)²) = √13

AC = √((2+4)² + (-3 +3)²) = √36 = 6

The lengths of the sides of ΔDEF are;

DE = √25=5

EF = √13

DF = √36 = 6

As,

AB= DE, BC = EF , AC= DF

So, By SSS congruency criteria ΔABC ≅ ΔDEF

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1 year ago

Answer my math question I asked so many times I lost most of points by

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Answer:

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Step-by-step explanation:

equation: y = x - 6 + x^2

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I figured this out by looking at the point (6,0). To get 0 (y), you have to subtract 6. Knowing this, I subtracted 6 from the rest of the coordinates, leaving me with numbers that are able to be squared to get y. This led me to the equation x - 6 + x^2.

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3 years ago

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The answer to the question

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2 years ago

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2 years ago

1. Taylor needs to purchase a car. The car Taylor plans to purchase costs $10,000. Taylor has saved $2,000 to use as a down paym

Alexxandr [17]

Answer:

a. The amount Taylor will need to finance is $8,000

b. The amount Taylor pays as interest in one year is $400

Step-by-step explanation:

The given parameters of the financing for the car are;

The cost of the car Taylor plans to purchase, C = $10,000

The amount Taylor has saved to be used as down payment, S = $2,000

The interest rate of the credit Taylor is offered = 5%

The duration given for repayment of the loan = 5 years

a. To purchase the car, the amount Taylor will need to finance, 'P', is given as follows;

P = C - S

∴ P = $10,000 - $2,000 = $8,000

b. The amount of interest on the loan in one year, 'I', is given by the following formula;

$I = \dfrac{P \times R \times T}{100}$

Where;

I = The interest payed

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R = The interest rate = 5% APR

T = The time period the interest is applied = 1 year

Plugging in the values, we get;

$I = \dfrac{\$ \, 8,000 \times 5 \times 1}{100} = \$ \, 400$

The interest Taylor will pay on the loan in one year, I = $4,00

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3 years ago