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3 years ago

Copy the diagram and calculate the sizes of x°, yº and zº. What is the sum of the angles of the

Mathematics

2 answers:

Dominik [7]3 years ago

5 0

Answer:

180

Step-by-step explanation:

to find angle :

x =180 - 150=30

y =180-80=100

z = 180-130=50

so, 30+50+100=180

artcher [175]3 years ago

4 0

Angle x = 30 degrees
Angle y= 100 degrees
Angle z = 50 degrees
Sum of the angles = 180 degrees

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What is the diameter and radius also the area

serious [3.7K]

Radius-24, diameter-48, area-1809.56

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3 years ago

2(3b-1)=40 Simplify.

timofeeve [1]

Answer:b=7

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

2(3b−1)=40

(2)(3b)+(2)(−1)=40(Distribute)

6b+−2=40

6b−2=40

Step 2: Add 2 to both sides.

6b−2+2=40+2

6b=42

Step 3: Divide both sides by 6.

6b/6=42/6

b=7

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2 years ago

State if the two triangles are congruent, if they are state how you know.

Mnenie [13.5K]

Answer:

I belive it would be HL because its defenitly not SSS

Step-by-step explanation:

HL Postulate is if the hypotenuse and leg of one right triangle are congruent to the hypotenuse and leg of another right triangle, then the two triangles are congruent.

4 0

3 years ago

What two numbers multiply to -270 and add up to -3

GrogVix [38]

Answer:

-18 and 15

-18 + 15 = -3

-18 x 15 = -270

6 0

2 years ago

Parallel / Perpendicular Practice

deff fn [24]

The slope and intercept form is the form of the straight line equation that includes the value of the slope of the line

Neither
║
Neither
⊥
║
Neither
Neither
Neither

Reason:

The slope and intercept form is the form y = m·x + c

Where;

m = The slope

Two equations are parallel if their slopes are equal

Two equations are perpendicular if the relationship between their slopes, m₁, and m₂ are; $m_1 = -\dfrac{1}{m_2}$

1. The given equations are in the slope and intercept form

$\ y = 3 \cdot x + 1$

The slope, m₁ = 3

$y = \dfrac{1}{3} \cdot x + 1$

The slope, m₂ = $\dfrac{1}{3}$

Therefore, the equations are neither parallel or perpendicular

Neither

2. y = 5·x - 3

10·x - 2·y = 7

The second equation can be rewritten in the slope and intercept form as follows;

$y = 5 \cdot x -\dfrac{7}{2}$

Therefore, the two equations are parallel

3. The given equations are;

-2·x - 4·y = -8

-2·x + 4·y = -8

The given equations in slope and intercept form are;

$y = 2 -\dfrac{1}{2} \cdot x$

Slope, m₁ = $-\dfrac{1}{2}$

$y = \dfrac{1}{2} \cdot x - 2$

Slope, m₂ = $\dfrac{1}{2}$

The slopes

Therefore, m₁ ≠ m₂

$m_1 \neq -\dfrac{1}{m_2}$

The lines are Neither parallel nor perpendicular

Neither

4. The given equations are;

2·y - x = 2

$y = \dfrac{1}{2} \cdot x +1$

m₁ = $\dfrac{1}{2}$

y = -2·x + 4

m₂ = -2

Therefore;

$m_1 \neq -\dfrac{1}{m_2}$

Therefore, the lines are perpendicular

5. The given equations are;

4·y = 3·x + 12

-3·x + 4·y = 2

Which gives;

First equation, $y = \dfrac{3}{4} \cdot x + 3$

Second equation, $y = \dfrac{3}{4} \cdot x + \dfrac{1}{2}$

Therefore, m₁ = m₂, the lines are parallel

6. The given equations are;

8·x - 4·y = 16

Which gives; y = 2·x - 4

5·y - 10 = 3, therefore, y = $\dfrac{13}{5}$

Therefore, the two equations are neither parallel nor perpendicular

Neither

7. The equations are;

2·x + 6·y = -3

Which gives $y = -\dfrac{1}{3} \cdot x - \dfrac{1}{2}$

12·y = 4·x + 20

Which gives

$y = \dfrac{1}{3} \cdot x + \dfrac{5}{3}$

m₁ ≠ m₂

$m_1 \neq -\dfrac{1}{m_2}$

Neither

8. 2·x - 5·y = -3

Which gives; $y = \dfrac{2}{5} \cdot x +\dfrac{3}{5}$

5·x + 27 = 6

$x = -\dfrac{21}{5}$

Therefore, the slopes are not equal, or perpendicular, the correct option is Neither

Learn more here:

brainly.com/question/16732089

6 0

2 years ago