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Stels [109]
3 years ago
5

Simplify the expression square root 100 over 49

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
5 0
Just plug in the square root of 100 in your calculator (10) and then either leave it as 10/49 or simplify it to a decimal...depending on what your teacher is expecting from you.
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Which table does not represent a relationship that is directly proportional? Btw i clicked a by accident
Ad libitum [116K]

Answer:

The selected option

Step-by-step explanation:

Coincidentally, you answered correctly.

From the values of 3 and five, we can assume that the function of the table is Y=x+2.

But if we move to the next value pairs, that function is false.

10=6+2 that isn't correct.

If you apply this to all the pairs in the table you will find that there is not a function that represents the values given. Therefore, the first option is correct.

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2 years ago
Fifty- three students from 32 different schools signed up for a multi-classroom project. About how many students signed up for t
inessss [21]
Hello there.

<span>Fifty- three students from 32 different schools signed up for a multi-classroom project. About how many students signed up for the project? 

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3 years ago
Read 2 more answers
GETS BRAINILIST!!!!The table shows the relationship between the number of drops of food color added to different number of cups
Kryger [21]

Answer:

I would say the first one

Step-by-step explanation:

A graph is shown. The title of the graph is Cake Decorating. The horizontal axis label is Frosting in cups. The horizontal axis values are 0, 10, 20, 30, 40, 50, 60. The vertical axis label is Food Color in drops. The vertical axis values are 0, 20, 40, 60, 80, 100, 120.

8 0
3 years ago
Find the area under the standard normal probability distribution between the following pairs of​ z-scores. a. z=0 and z=3.00 e.
prohojiy [21]

Answer:

a. P(0 < z < 3.00) =  0.4987

b. P(0 < z < 1.00) =  0.3414

c. P(0 < z < 2.00) = 0.4773

d. P(0 < z < 0.79) = 0.2852

e. P(-3.00 < z < 0) = 0.4987

f. P(-1.00 < z < 0) = 0.3414

g. P(-1.58 < z < 0) = 0.4429

h. P(-0.79 < z < 0) = 0.2852

Step-by-step explanation:

Find the area under the standard normal probability distribution between the following pairs of​ z-scores.

a. z=0 and z=3.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 3.00) = 0.9987

Thus;

P(0 < z < 3.00) = 0.9987 - 0.5

P(0 < z < 3.00) =  0.4987

b. b. z=0 and z=1.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 1.00) = 0.8414

Thus;

P(0 < z < 1.00) = 0.8414 - 0.5

P(0 < z < 1.00) =  0.3414

c. z=0 and z=2.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 2.00) = 0.9773

Thus;

P(0 < z < 2.00) = 0.9773 - 0.5

P(0 < z < 2.00) = 0.4773

d.  z=0 and z=0.79

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 0.79) = 0.7852

Thus;

P(0 < z < 0.79) = 0.7852- 0.5

P(0 < z < 0.79) = 0.2852

e. z=−3.00 and z=0

From the standard normal distribution tables,

P(Z< -3.00) = 0.0014  and P(Z< 0) = 0.5

Thus;

P(-3.00 < z < 0 ) = 0.5 - 0.0013

P(-3.00 < z < 0) = 0.4987

f. z=−1.00 and z=0

From the standard normal distribution tables,

P(Z< -1.00) = 0.1587  and P(Z< 0) = 0.5

Thus;

P(-1.00 < z < 0 ) = 0.5 -  0.1586

P(-1.00 < z < 0) = 0.3414

g. z=−1.58 and z=0

From the standard normal distribution tables,

P(Z< -1.58) = 0.0571  and P(Z< 0) = 0.5

Thus;

P(-1.58 < z < 0 ) = 0.5 -  0.0571

P(-1.58 < z < 0) = 0.4429

h. z=−0.79 and z=0

From the standard normal distribution tables,

P(Z< -0.79) = 0.2148  and P(Z< 0) = 0.5

Thus;

P(-0.79 < z < 0 ) = 0.5 -  0.2148

P(-0.79 < z < 0) = 0.2852

8 0
3 years ago
What is the volume of a cone (in cubic inches) with a radius of 6 inches and a height of 3 inches? Use 3.14 for π. Round your an
ICE Princess25 [194]

When you square the radius = 6×6= 36. Multiply 36×3×3.14=339.12. Using the formula, you then multiply 1/3×339.12=339.12/3= 113.04 in^3. Final answer is 113.04^3

4 0
3 years ago
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