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vesna_86 [32]
3 years ago
13

A motorcycle slows down uniformly from a speed of 21 m/s to rest in 6.0s. How far did it travel during this time?

Physics
1 answer:
Verizon [17]3 years ago
7 0

Answer:

63 m

Explanation:

The initial velocity of the motorcycle is

v_i = 21 m/s

The final velocity is

v_f = 0

And the time taken is

t=6.0 s

Since the acceleration of the motorcycle is uniform, we can find the distance traveled by the motorcycle during this time by using the following SUVAT equation:

S=\frac{1}{2} (v_i +v_f) t

Substituting numbers into the equation, we find

S=\frac{1}{2}( 21 m/s + 0)(6.0 s)=63 m

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