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3 years ago

A motorcycle slows down uniformly from a speed of 21 m/s to rest in 6.0s. How far did it travel during this time?

Physics

1 answer:

Verizon [17]3 years ago

7 0

Answer:

63 m

Explanation:

The initial velocity of the motorcycle is

$v_i = 21 m/s$

The final velocity is

$v_f = 0$

And the time taken is

$t=6.0 s$

Since the acceleration of the motorcycle is uniform, we can find the distance traveled by the motorcycle during this time by using the following SUVAT equation:

$S=\frac{1}{2} (v_i +v_f) t$

Substituting numbers into the equation, we find

$S=\frac{1}{2}( 21 m/s + 0)(6.0 s)=63 m$

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