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hram777 [196]
3 years ago
14

How much heat is needed to bring 12.0 g of water from 28.3 °C to 43.87 °C, if the specific heat capacity of water is 4.184 J/(g•

°C)?
Physics
1 answer:
Vika [28.1K]3 years ago
7 0

Answer:

Heat capacity, Q = 781.74 Joules

Explanation:

Given the following data;

Mass = 12g

Initial temperature = 28.3°C

Final temperature = 43.87°C

Specific heat capacity of water = 4.184J/g°C

To find the quantity of heat needed?

Heat capacity is given by the formula;

Q = mcdt

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

dt = T2 - T1

dt = 43.87 - 28.3

dt = 15.57°C

Substituting into the equation, we have;

Q = 12*4.184*15.57

Q = 781.74 Joules

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Answer: Carbon 14 and Uranium 238 are not used together to determine fossil ages.

Explanation:

Carbon 14 with a half life of 5,700 years can only be used to date fossils of approximately 50,000 years. Most fossils are thought to be much older than 50,000 years. Also most fossils no longer contain any Carbon. The fossilized remains have been mineralized where the original organic material has been replaced and turned into stones containing no carbon.

Uranium 238 has a half life of 4.5 billion years. Uranium can be used to date the age of the earth. If 50% of pure uranium' is left in a sample the sample is assumed to be 4.5 billion years old.( This is assuming that the original sample was 100% uranium and no Uranium 238 has been eroded or lost in 4.5 billion years old. If a fossil has only 25 % of the Uranium 238 the sample has an estimated age of 3.2 Billion years. This would be the estimated age of the earliest life or formation of fossils.

Note no fossils contain Uranium 238. Uranium 238 is only found in igneous or volcanic rocks. So no fossils can be dated directly using U 238.

Because of the huge differences in the half lives of Carbon 14 and Uranium238 they cannot be used together. Carbon 14 can only be used to date fossils of a very recent age. Uranium 238 can only be used to date volcanic rocks of a very old age.

3 0
2 years ago
What are the three factors needed for Newton’s Second Law?
Anastasy [175]

Answer:

the weight of the object, the force of gravity acting on said object, and the mass of the object are needed for Newton's second law of motion.

5 0
3 years ago
Find the noise level of a sound having an intensity of 1.5x10^-14W/m^2 given I0=10^12 W/m2
Llana [10]

Answer:

Noise level will be -18.2 watt

So option (b) will be correct answer

Explanation:

We have given sound intensity I=1.5\times 10^{-14}w/m^2

And threshold intensity I_0=\times 10^{-12}w/m^2 ( in question it is given as 10^{12}w/m^2 but its standard value is 10^{-12}w/m^2 )

Now noise level  =10log\frac{I}{I_0}=10log\frac{1.5\times 10^{-14}}{10^{-12}}=10log0.015-18.23

So the noise level will be -18.2

So option (b) will be correct answer

5 0
3 years ago
15) What is the momentum of a 280 kg motorcycle moving with a velocity of 15 m/s?
enot [183]

Answer:

..

Explanation:

6 0
2 years ago
Suppose the ends of a 27-m-long steel beam are rigidly clamped at 0°C to prevent expansion. The rail has a cross-sectional area
frozen [14]

Answer:

F = 1.58*10^{11} N

Explanation:

given data:

length of steel beam = 27 m

cross sectional area of rail = 35 cm

\Delta T = 39 Degree celcius

change in length of steel beam is given as

\Delta L = L_O \alpha \Delta T

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Young's modulus is

Y = \frac{FL}{A\Delta L}

F = \frac{ YA\Delta L}{L}

= \frac{2.0*10^{11}*25*10^{-4}8.58*10^{-3}}{27}

F = 1.58*10^{11} N

5 0
3 years ago
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