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N76 [4]
2 years ago
9

Think of an example of a chemical change that some people might think is NOT a chemical change. Explain why it is.​

Physics
1 answer:
AlekseyPX2 years ago
7 0

Answer:

Digesting food

Explanation:

I have people who think that its not true but it is

Hope this helped

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Explain the difference between balanced forces and action and reaction forces.
Monica [59]
Action-reaction forces<span> act on different objects; </span>balanced forces<span> act on the same object. </span>Balanced forces<span> can result in acceleration, </span>action-reaction forces<span> cannot. ... Newton's Third Law of Motion does not apply to </span>balanced forces<span>.</span>
5 0
3 years ago
An old millstone, used for grinding grain in a gristmill, is a solid cylindrical wheel that can rotate about its central axle wi
MAXImum [283]

Answer:

The answer is I=70,513kgm^2

Explanation:

Here we will use the rotational mechanics equation T=Ia, where T is the Torque, I is the Moment of Inertia and a is the angular acceleration.

When we speak about Torque it´s basically a Tangencial Force applied over a cylindrical or circular edge. It causes a rotation. In this case, we will have that T=Ft*r, where Ft is the Tangencial Forge and r is the radius

Now we will find the Moment of Inertia this way:

Ft*r=I*a -> (Ft*r)/(a) = I

Replacing we get that I is:

I=(200N*0,33m)/(0,936rad/s^2)

Then I=70,513kgm^2

In case you need to find extra information, keep in mind the Moment of Inertia for a solid cylindrical wheel is:  

I=(1/2)*(m*r^2)

4 0
3 years ago
A particle with charge 6 mC moving in a region where only electric forces act on it has a kinetic energy of 1.9000000000000001 J
Vesna [10]

Answer:

16.9000000000000001 J

Explanation:

From the given information:

Let the initial kinetic energy from point A be K_A = 1.9000000000000001 J

and the final kinetic energy from point B be K_B = ???

The charge particle Q = 6 mC = 6 × 10⁻³ C

The change in the electric potential from point B to A;

i.e. V_B - V_A = -2.5 × 10³ V

According to the work-energy theorem:

-Q × ΔV = ΔK

-Q \times ( V_B - V_A) = (K_B - K_A)

-(6\times 10^{-3}\ C) \times ( -2.5 \times 10^3) = (K_B - 1.9000000000000001 \ J)

15 = (K_B - 1.9000000000000001 \ J)

K_B = 15+ 1.9000000000000001 \ J

\mathbf{K_B =1 6.9000000000000001 \ J}

3 0
3 years ago
Please help me ,create a slogan that promotes the role of internet in education
aleksklad [387]

Answer:

¨Facts you didn´t know¨ or ¨unknown facts¨

Explanation:

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What is the displacement of the object from 2 seconds to 6 seconds?
masya89 [10]

the answer would be 4

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