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2 years ago

12

You and your little sister go to the park in cheetah started to go down the plastic slide. On her way down to euros out ouch! Wh

en you rush over to ask her what happened she replied the slide shocked me. Explain why this event took place using the distribution of charges.

1 answer:

gulaghasi [49]2 years ago

7 0

As you slide down the plastic slide, electrons move from the plastic to you. ... Touch another person or an object (anything that isn't negatively charged by extra electrons) and ZAP! The electrons move from you to the other object. You get a shock

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Answer:

The light bends away from the normal

Explanation:

We can solve the problem by using Snell's law:

$n_1 sin \theta_1 = n_2 sin \theta_2$

where:

$n_1$ is the index of refraction of the first medium

$n_2$ is the index of refraction of the second medium

$\theta_1$ is the angle of incidence (angle between the incoming ray and the normal to the interface)

$\theta_2$ is the angle of refraction (angle between the outcoming ray and the normal to the interface)

We can rearrange the equation as

$sin \theta_2 = \frac{n_1}{n_2}sin \theta_1$

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$n_1 > n_2$

Therefore, the term $\frac{n_1}{n_2}$ is greater than 1, so

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which means that the angle of refraction is greater than the angle of incidence, and so the light will bend away from the normal.

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2 years ago

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2 years ago

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Answer:

1. $\theta=29.84^{0}$

2. $\theta=60.15^{0}$

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$I=\frac{I_{0} }{2}$

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$I=327.5\frac{W}{m^{2} }$

For a smaller angle for the first polarizer:

According to Malus Law

$I_{2} =I_{1} Cos^{2}(90^{0} - \theta)$

$I_{2} =I_{1} sin^{2}\theta$

$\frac{I_{2} }{I_{1} }=Sin^{2}\theta$

taking square root on both sides

$\sqrt{\frac{163}{327.5} } = sin\theta$

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For a larger angle for the first polarizer:

According to Malus Law

$I_{2} =I_{1} cos^{2}\theta$

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$\theta=60.15^{0}$

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