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Phoenix [80]
3 years ago
12

You and your little sister go to the park in cheetah started to go down the plastic slide. On her way down to euros out ouch! Wh

en you rush over to ask her what happened she replied the slide shocked me. Explain why this event took place using the distribution of charges.
Physics
1 answer:
gulaghasi [49]3 years ago
7 0
As you slide down the plastic slide, electrons move from the plastic to you. ... Touch another person or an object (anything that isn't negatively charged by extra electrons) and ZAP! The electrons move from you to the other object. You get a shock
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A scientist measures the growth of a bamboo plant over time. The table below shows the results.
mihalych1998 [28]
A. 1.35 is the number in between 1.2 and 1.5.
3 0
2 years ago
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A wave has a frequency of 875 hz and a wavelength of 352 m. At what speed is this wave traveling 
Sonbull [250]

Answer:

308,000 or 30.8×10^3

Explanation:

v=f×lamda

v is ?, f is 875Hz, lamda is 352m

v=875×352

v=308,000

v=30.8×10^3 m/s

5 0
3 years ago
Can someone please answer this, ill give you brainliest Would be very appreciated.
marshall27 [118]

Answer:

cohesive properties

Explanation:

The property of cohesion allows liquid water to have <u>no tension on the surface</u>.

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2 years ago
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A trip is taken that passes through the following points in order
IgorLugansk [536]

Answer:

The displacement from point B to point E is 25.0 m left

8 0
3 years ago
You obtain a 100-W light bulb and a 50-W light bulb. Instead of connecting them in the normal way, you devise a circuit that pla
lesantik [10]

Answer:

When they are connected in series

     The  50 W bulb glow more than the 100 W bulb

Explanation:

From the question we are told that

     The power rating  of the first bulb is P_1  = 100 \ W

      The power rating of the second bulb is  P_2  =  50 \ W

     

Generally the power rating of the first bulb is mathematically represented as

      P_1  =  V^2 R

Where  V is the normal household voltage which is constant for both bulbs

  So  

        R_1  =  \frac{V^2}{P_1 }

substituting values

        R_1  =  \frac{V^2}{100}

Thus the resistance of the second bulb would be evaluated as

       R_2  =  \frac{V^2}{50}

From the above calculation we see that

        R_2  >  R_1

This power rating of the first bulb can also be represented mathematically as  

        P_  1  =  I^2_1  R_1

This power rating of the first bulb can also be represented mathematically as    

       P_  2  =  I^2_2 R_2

Now given that they are connected in series which implies that the same current flow through them so

       I_1^2 =  I_2^2

This means  that

       P \ \alpha  \  R

So  when they are connected in series

     P_2  >  P_1

This means that the 50 W bulb glows more than the 100 \ W bulb

3 0
3 years ago
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