3 years ago

What is the percentage of magnesium sulfate in MgSO4 x 7H2O.

1 answer:

5 0

48.78%
Percentage of MgSO4 = mass of MgSO4/ mass of sample (MgSO4. 7H20) and multiply it by 100.

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spin [16.1K]

Answer : The molar concentration of solution is $7.06\times 10^{-6}mol/L$

Explanation :

Using Beer-Lambert's law :

$A=\epsilon \times C\times l$

where,

A = absorbance of solution = 0.614

C = molar concentration of solution = ?

l = path length = 1.0 cm

$\epsilon$ = molar absorptivity coefficient = $87000M^{-1}cm^{-1}$ (assume)

Now put all the given values in the above formula, we get:

$0.614=(87000M^{-1}cm^{-1})\times C\times (1.0cm)$

$C=0.00000705747mol/L=7.06\times 10^{-6}mol/L$

Therefore, the molar concentration of solution is $7.06\times 10^{-6}mol/L$

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