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quester [9]
3 years ago
11

An albatross can fly 400 kilometers in 8 hours at a constant speed using d as distance and t as number of hours. An equation tha

t represents this situation is d=50t what are two contants of proportionality for the relationship between distance in kilometers and number of hours? What is the relaionship between the two values?
Mathematics
1 answer:
kow [346]3 years ago
4 0

Answer:

Constant of Proportionality is 50.  

Step-by-step explanation:

Albatross can fly 400 kilometers in 8 hours.

'd' represents the distance and 't' represents the number of hours.

The equation d=50t represents the relationship between the distance and time.

Now, in the equation shown above 50 is the constant of proportionality, and 50 represents the rate of change of distance with time.

The constant of proportionality tells us the rate of change between two variables.

So for every 1 hour of time the distance covered is 50 kilometers.  

 

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The curves r1(t) = 2t, t2, t4 and r2(t) = sin t, sin 5t, 2t intersect at the origin. Find their angle of intersection, θ, correc
masya89 [10]

Answer:

Therefore the angle of intersection is \theta =79.48^\circ

Step-by-step explanation:

Angle at the intersection point of two carve is the angle of the tangents at that point.

Given,

r_1(t)=(2t,t^2,t^4)

and r_2(t)=(sin t , sin5t, 2t)

To find the tangent of a carve , we have to differentiate the carve.

r'_1(t)=(2,2t,4t^3)

The tangent at (0,0,0) is     [ since the intersection point is (0,0,0)]

r'_1(0)=(2,0,0)      [ putting t= 0]

|r'_1(0)|=\sqrt{2^2+0^2+0^2} =2

Again,

r'_2(t)=(cos t ,5 cos5t, 2)

The tangent at (0,0,0) is    

r'_2(0)=(1 ,5, 2)        [ putting t= 0]

|r'_1(0)|=\sqrt{1^2+5^2+2^2} =\sqrt{30}

If θ is angle between tangent, then

cos \theta =\frac{r'_1(0).r'_2(0)}{|r'_1(0)|.|r'_2(0)|}

\Rightarrow cos \theta =\frac{(2,0,0).(1,5,2)}{2.\sqrt{30} }

\Rightarrow cos \theta =\frac{2}{2\sqrt{30} }

\Rightarrow cos \theta =\frac{1}{\sqrt{30} }

\Rightarrow  \theta =cos^{-1}\frac{1}{\sqrt{30} }

\Rightarrow  \theta =79.48^\circ

Therefore the angle of intersection is \theta =79.48^\circ.

8 0
3 years ago
Is there a rigid transformation that maps triangle ABC to triangle ABD? If so, which transformation?
MissTica

Answer: option C!

Step-by-step explanation:

i just got it right

7 0
3 years ago
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Classify the equation, 7x+6=7x-5, as having one solution, no solution, or infinitely many solutions.
Ksenya-84 [330]

Answer:

Step-by-step explanation:

7x + 6 = 7x - 5

Collecting like terms

7x - 7x = -5 - 6

The x is canceled out so no solution

5 0
3 years ago
What is the decay factor in the exponential decay function y=a (1-r) t
MrRissso [65]

Answer:

in this form, the "-r" would cause the result to decrease

I assume that the answer is "r"

if r = .1 (10 %) then 1-.1 = .9

if you have 100 items then y = 100(.9)^1 = 90

the total decreased by 10% ... y = 100(.9)^2 after 2 time periods

Step-by-step explanation:

5 0
2 years ago
A person's blood glucose level and diabetes are closely related. Let x be a random variable measured in milligrams of glucose pe
soldier1979 [14.2K]

Using the normal distribution, it is found that:

a) 0.8599 = 85.99% probability that x is more than 60.

b) 0.1788 = 17.88% probability that x is less than 110.

c) 0.6811 = 68.11% probability that x is between 60 and 110.

d) 0.0643 = 6.43% probability that x is greater than 125.

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

  • The mean is of 87, thus \mu = 87.
  • The standard deviation is of 25, thus \sigma = 25.

Item a:

This probability is <u>1 subtracted by the p-value of Z when X = 60</u>, thus:

Z = \frac{X - \mu}{\sigma}

Z = \frac{60 - 87}{25}

Z = -1.08

Z = -1.08 has a p-value of 0.1401.

1 - 0.1401 = 0.8599

0.8599 = 85.99% probability that x is more than 60.

Item b:

This probability is the <u>p-value of Z when X = 110</u>, thus:

Z = \frac{X - \mu}{\sigma}

Z = \frac{110 - 87}{25}

Z = 0.92

Z = 0.92 has a p-value of 0.8212.

1 - 0.8212 = 0.1788.

0.1788 = 17.88% probability that x is less than 110.

Item c:

This probability is the <u>p-value of Z when X = 110 subtracted by the p-value of Z when X = 60</u>.

From the previous two items, 0.8212 - 0.1401 = 0.6811.

0.6811 = 68.11% probability that x is between 60 and 110.

Item d:

This probability is <u>1 subtracted by the p-value of Z when X = 125</u>, thus:

Z = \frac{X - \mu}{\sigma}

Z = \frac{125 - 87}{25}

Z = 1.52

Z = 1.52 has a p-value of 0.9357.

1 - 0.9357 = 0.0643.

0.0643 = 6.43% probability that x is greater than 125.

A similar problem is given at brainly.com/question/24863330

7 0
3 years ago
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