$\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount}
\\\\
A=Pe^{rt}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$4100\\
r=rate\to 7.25\%\to \frac{7.25}{100}\to &0.0725\\
t=years\to &8
\end{cases}
\\\\\\
A=4100e^{0.0725\cdot 8}\implies A=4100e^{0.58}\implies A\approx 7322.757566075$

8 0

3 years ago

Give an example of how the zero product property applies to solving quadratic equations

mestny [16]

Answer:

How the zero product property applies to solving quadratic equations?

The zero product property states that if the product of two quantities is zero, then one or both of the quantities must be zero. ... When you factor, you turn a quadratic expression into a product. If you have a quadratic expression equal to zero, you can factor it and then use the zero product property to solve.

Step-by-step explanation:

8 0

3 years ago

In the expression 5x + 15 = 150, you can start solving the problem

Gnoma [55]

Answer:

i think 2x

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers