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4 years ago

Let U represent the set of all people that frequently visit a certain restaurant, surveyed about which food they like best. Let

Mathematics

1 answer:

ankoles [38]4 years ago

7 0

Answer:

a) (C∪P)-B

b) (U-B)∩(U-C)∩(U-P)

c) B∩C∩P

d) P-(B∪C)

e) (B∪C)-P

Step-by-step explanation:

We can use three operations between sets:

Union: X∪Y is the set of elements that belong to X or belong to Y
Intersection: X∩Y is the set of elements that belong to X and belong to Y
Difference: X-Y is the set of elements that belong to X and NOT belong to Y.

The sets we can use in each part are U,B,C and P

a) A customer that likes corn dogs belongs to C, and a customer that likes pizza belongs to P, then a customer who likes corn dogs or pizza belongs to C∪P. The customers from this problem do not like burgers, so they don't belong to B. From this, the required set is (C∪P)-B

b) The customers do not like burgers, so they do not belong to B. However, they visit the restaurant so they belong to U. Thus, the customers belong to U-B. Similarly, because the customers do not like corn dogs and do not like pizza, they belong to U-C and U-P. Then the set of customers is (U-B)∩(U-C)∩(U-P).

c) The customers are in B, C and P so they belong to B∩C∩P.

d) The customers belong to P (they like pizza) but they do not belong to (B∪C), thus they belong to P-(B∪C)

e) The customers belong to B∪C but they do not belong to P, so the required set is (B∪C)-P.

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Answer:

8x9.82= 78.56

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3 years ago

35 POINTS!!!!!

zvonat [6]

Answer:

Hello, Your answer will be

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3 years ago

involving the selection of two apples from a bag of red and yellow apples without replacement. Assume that the bag has a total o

ivolga24 [154]

Answer:

1) The probability that the second apple is red is 0.7143 (71.43%).

2) The probability that at least one red apple is picked 0.9341 (93.41%).

Step-by-step explanation:

We can make a probability tree as the attached picture.

1) There are 2 ways in the probability tree when the second apple is red:

Both apples are red:

P(R∩R)= $\frac{10}{14}\frac{9}{13}$ =0.4945

Only the second apple is red:

P(Y∩R)= $\frac{4}{14}\frac{10}{13}$ =0.2198

The probability that the second apple is red is the sum of the previous probabilities.

P(2nd R)=P(R∩R)+P(Y∩R)=0.4945+0.2198=0.7143

2) To find the probability that at least one apple is red, we can get the probability of none of the apples is red and then it will be subtracted from 1.

The way in the probability tree is Y∩Y:

P(Y∩Y)= $\frac{4}{14} \frac{3}{13}$ =0.0659