We are given the following data: <span>x = 2t, y = t + 5, -2 ≤ t ≤ 3. The data is valid since there are three unknowns in this problem and that three equations would suffice to answer the problem.
We start with the given </span>-2 ≤ t ≤ 3 then substitute y = t +5 by using the limits of the range:
at t = -2 ; y = -2 + 5 = 3
at t = 3, y = 3+5 = 8
for the second equation
at t = -2 ; x = 2*-2 =-4
at t=3; x = 2*3 = 6
we group the points based on their original corresponding t's
(3,-4) and (8,6) we just have to connect these points along with the internal points in between. The relationship should be linear.
Answer:
Did you cop the strawberry coughs?
Step-by-step explanation:
Xy = -10/ 4
= -2.5
So, xy = -2.5
Answer:
the answer for A is 27 and B is 36 and C is 82
Answer:
The standard form is 8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11
The degree of given polynomial is '5'
the co-efficient of y⁴ is '-17'
Step-by-step explanation:
Given standard form 2 y²+ 6 y³-11-17 y⁴+8 y⁵
<em>The form ax² + b x + c is called the standard form of the quadratic expression of 'x'.This is second degree standard form of polynomial.</em>
<em>The form ax⁵ + b x⁴ + c x³ +d x² +ex +f is called the standard form of the quadratic expression of 'x'.This is fifth degree standard form of polynomial</em>
now Given polynomial is 2 y²+ 6 y³-11-17 y⁴+8 y⁵
The standard form is
8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11
<u><em>Conclusion</em></u>:-
<em>The degree of given polynomial is '5'</em>
<em>The co-efficient of y⁴ is '-17'</em>
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