log(4) + log(2) - log(5)
= log(2²) + log(2) - log(5)
= 2 log(2) + log(2) - log(5)
= 3 log(2) - log(5)
= log(2³) - log(5)
= log (2³/5)
= log (8/5)
= log (1.6) = 0.2041... (rounded)
Answer:
5 units
Step-by-step explanation:
Let point O be the point of intersection of the kite diagonals.
|OF| = 2, |OH| = 5
|FH| = |OF| + |OH| = 2 + 5 = 7
FH and EG are the diagonals of the kite. Hence the area of thee kite is:
Area of kite EFGH = (FH * EG) / 2
Substituting:
35 = (7 * |EG|) / 2
|EG| * 7 = 70
|EG| = 10 units
The longer diagonal of a kite bisects the shorter one, therefore |GO| = |EO| = 10 / 2 = 5 units
x = |GO| = |EO| = 5 units
Answer:
(1) 2 (2) (-1/2,0) (3) (0,1)
Step-by-step explanation:
The slope of the line is the number times x. This equation is y=mx+b, where m is the slope and b is the y-intercept. In this case, m is 2, so we have our slope. The y-intercept is easy, as we already know it to be (0,1). The x-intercept is the point where the line hits x when y=0. To solve for the x-intercept, we set y to 0 and solve. We have 0=2x+1. First, we subtract 1 from both sides and get -1=2x. Next, to get x by itself, divide both sides by 2. Now we have -1/2=x. Now we have our x coordinate for our x-intercept. Because of this, we get (-1/2,0) as our x-intercept.
